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저는 실제로 JPA2.0을 배우고 있습니다. 다음과 같은 오류가있어서 IDE로 Eclipse를 사용하고 있습니다. JPA 2.0, 어떻게하면 다음 2 가지 오류를 해결할 수 있습니까?
Exception in thread "main" javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute query
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1215)
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1148)
at org.hibernate.ejb.QueryImpl.getSingleResult(QueryImpl.java:307)
at com.banking.core.persistence.utils.EntityManagerTest.main(EntityManagerTest.java:38)
Caused by: org.hibernate.exception.SQLGrammarException: could not execute query
at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:92)
at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66)
at org.hibernate.loader.Loader.doList(Loader.java:2536)
at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2276)
at org.hibernate.loader.Loader.list(Loader.java:2271)
at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:452)
at org.hibernate.hql.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:363)
at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:196)
at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1268)
at org.hibernate.impl.QueryImpl.list(QueryImpl.java:102)
at org.hibernate.ejb.QueryImpl.getSingleResult(QueryImpl.java:274)
... 1 more
Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'loanaccoun0_.id' in 'field list'
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
at java.lang.reflect.Constructor.newInstance(Unknown Source)
at com.mysql.jdbc.Util.handleNewInstance(Util.java:411)
at com.mysql.jdbc.Util.getInstance(Util.java:386)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1052)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3597)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3529)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1990)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2151)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2625)
at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2119)
at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:2281)
at org.hibernate.jdbc.AbstractBatcher.getResultSet(AbstractBatcher.java:208)
at org.hibernate.loader.Loader.getResultSet(Loader.java:1953)
at org.hibernate.loader.Loader.doQuery(Loader.java:802)
at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:274)
at org.hibernate.loader.Loader.doList(Loader.java:2533)
... 9 more
이 내가 지금 사용하고 쿼리
...LoanAccount.class
@Entity
@Table(schema="BANKING_CORE", name="NUMBER_OF_PAYMENTS")
@DiscriminatorValue("LA")
@NamedQuery(name = "LoanAccount.findByNumberofPayments", query = "SELECT lc from LoanAccount lc WHERE lc.numberOfPayments = :number_of_payments")
이것은 쿼리 자체
entitymanger.class입니다
LoanAccount lc = (LoanAccount) em.createNamedQuery("LoanAccount.findByNumberofPayments").setParameter("number_of_payments", 25).getSingleResult();
System.out.println(lc.getNumberOfPayments()+" "+lc.getCutOffDate());