jpa를 실행하는 데 문제가 있습니다. 생성자 공공 de.test.pages.LoginPage()를 사용하여 페이지를 초기화 할 수 없습니다NoViableAltException jpa를 사용하는 경우
근본 원인 :
NoViableAltException (내가
Login.java에WicketMessage Login.java를 실행하려고하면 다음과 같은 예외가 나타납니다 93 =! selectExpression은 [Object node]를 반환합니다. (n = aggregateExpression | n = scalarExpression | OBJECT LEFT_ROUND_BRACKET n = variableAccessOrTypeConstant RIGHT_ROUND_BRACKET | n = constructorExpression | n = mapEntryExpression)]] at org.eclipse.persistence. internal.jpa.parsing.jpql.antlr.JPQLParser.selectExpression (JPQLParser.java:5893) at org.eclipse.persistence.internal.jpa.parsing.jpql.antlr.JPQLParser.selectItem (JPQLParser.java:1356) at org.eclipse.persistence.internal.jpa.parsing.jpql.antlr.JPQLParser.selectClause (JPQLParser.java:1270) at org.eclipse.persistence.internal.jpa.parsing.jpql.antlr.JPQLParser.selectStatement (JPQLParser.java:351) at org.eclipse.persistence.internal.jpa.parsing.jpql. antlr.JPQLParser.document (JPQLParser.java:275) at org.eclipse.persistence.internal.jpa.parsing.jpql.JPQLParser.parse (JPQLParser.java:130) at org.eclipse.persistence.internal.jpa. org.eclipse.persistence.internal.jpa.EJBQueryImpl.buildEJBQLDatabaseQuery (EJBQueryImpl.java:207) at org.eclipse.persistence.internal.jpa.EJBQueryImpl에서 parsing.jpql.JPQLParser.buildParseTree (JPQLParser.java:91) 을 가져 오십시오. 부이 ldEJBQLDatabaseQuery (EJBQueryImpl.java:182) at org.eclipse.persistence.internal.jpa.EJBQueryImpl (EJBQueryImpl.java:134) at org.eclipse.persistence.internal.jpa.EJBQueryImpl (EJBQueryImpl.java:118) at org.eclipse.persistence.internal.jpa.EntityManagerImpl.createQuery (EntityManagerImpl.java:1352) at de.test.pages.LoginPage (알 수없는 소스) at java.lang.reflect.Constructor.newInstance (생성자. java : 513) at org.apache.wicket.session.DefaultPageFactory.createPage (DefaultPageFactory.java:192) at org.apache.wicket.session.DefaultPageFactory.newPage (DefaultPageFactory.java:57) at org.apache. wicket.request.target.component.BookmarkablePageRequestTarget.newPage (BookmarkablePageRequestTarget.java:298) at org.a pache.wicket.request.target.component.BookmarkablePageRequestTarget.getPage (BookmarkablePageRequestTarget.java:320) at org.apache.wicket.request.target.component.BookmarkablePageRequestTarget.processEvents (BookmarkablePageRequestTarget.java:234) at org.apache. org.apache.wicket.RequestCycle.step에서 org.apache.wicket.RequestCycle.processEventsAndRespond (RequestCycle.java:1250) 에서 wicket.request.AbstractRequestCycleProcessor.processEvents (AbstractRequestCycleProcessor.java:92) (RequestCycle.java:1329) at org.apache.wicket.RequestCycle.steps (RequestCycle.java:1428) at org.apache.wicket.RequestCycle.request (RequestCycle.java:545) at org.apache.wicket.protocol.http.WicketFilter. doGet (WicketFilter.java:479) at org.apache.wicket.protocol.http. (ApplicationFilterChain.java:188)에서 에서, at org.apache.catalina.core.StandardWrapperValve.invoke (StandardWrapperValve.java:213) at org.apache.catalina.core.StandardContextValve.invoke (StandardContextValve.java:172) at org.apache.catalina.core. StandardHostValve.invoke (StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke (ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke (StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service (CoyoteAdapter.java:174) at org.apache.coyote.http11.Http11Processor.process (Http11Processor.java:873) org.apache.coyote.http11.Http11BaseProtocol $ Http11ConnectionHandler.processConnection (Http11BaseProtocol.java:665) org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket (PoolTcpEndpoint.java:528) org.apache에서 에서 에서 . tomcat.util.net.LeaderFollowerWorkerThread.runIt (LeaderFollowerWorkerThread.java:81) at org.apache.tomcat.util.threads.ThreadPool $ ControlRunnable.run (ThreadPool.java:689) at java.lang.Thread.run (Thread.java:637)
메소드 LoginPage()는 다음과 같다 :
공개 LoginPage() {
EntityManagerFactory factory = Persistence.createEntityManagerFactory("quickstartUser");
EntityManager em = factory.createEntityManager();
// Read the existing entries
Query q = em.createQuery("SELECT * FROM quickstart_user");
// Persons should be empty
// Do we have entries?
int createNewEntries = q.getResultList().size();
Label label = new Label("result", "Result: ");
add(label);
// It is always good practice to close the EntityManager so that
// resources are conserved.
em.close();
persistance.xml
<persistence-unit name="quickstartUser" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
<property name="eclipselink.jdbc.driver" value="org.postgresql.Driver" />
<property name="eclipselink.jdbc.url" value="jdbc:postgresql://localhost:5432/test" />
<!-- I work in this example without user/password.-->
<property name="eclipselink.jdbc.user" value="" />
<property name="eclipselink.jdbc.password" value="" />
<!-- EclipseLink should create the database schema automatically -->
<property name="eclipselink.ddl-generation" value="drop-and-create-tables" />
<property name="eclipselink.ddl-generation.output-mode" value="database" />
</properties>
</persistence-unit>
테이블을 자동적으로 생성한다하더라도을 나는 나 자신으로 테이블을 만들어야했다.
적어도 엔티티 모델 QuickstartUser.java@Entity Public 클래스 QuickstartUser { @Id @GeneratedValue (전략 = GenerationType.TABLE) INT 개인 아이디; private 문자열 firstName; 전용 문자열 lastName; 전용 문자열 암호; 전용 문자열 사용자 이름;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
}는 읽기 주셔서 감사합니다.
BVA
안녕하세요, 결과가 돌아오고 예외가 사라졌습니다. 당신이했던 것처럼 쿼리를 사용하는 것에 대한 아이디어는 무엇입니까? –
JPA 쿼리 언어의 구문은 SQL과 유사하지만 SQL의 일부만 구현합니다. EntityManager는 SQL 쿼리를 허용하는 createNativeQuery 및 createNamedQuery를 제공하지만 createQuery는 JQL 만 지원합니다. –
이것은 끔찍한 예외 메시지이며 변경된 버그가있는 버그 (https://bugs.eclipse.org/bugs/show_bug.cgi?id=323038)를 제출했습니다. 관심이 있다면 버그에 투표하십시오. –