xslt를 xml 내용에 적용하십시오.

Question

xslt를 사용하고 있습니다. 내 XSLT가

<xsl:template match="tgroup"> 
<tr> 

    <xsl:if test="@cols"> 
     <xsl:attribute name="cols"> 
     <xsl:value-of select="@cols"/> 
     </xsl:attribute> 
    </xsl:if> 

    <xsl:if test="@colsep"> 
     <xsl:attribute name="colsep"> 
     <xsl:value-of select="@colsep"/> 
     </xsl:attribute> 
    </xsl:if> 
    <xsl:if test="@rowsep"> 
     <xsl:attribute name="rowsep"> 
     <xsl:value-of select="@rowsep"/> 
     </xsl:attribute> 
    </xsl:if> 
    <xsl:if test="@align"> 
     <xsl:attribute name="align"> 
     <xsl:value-of select="@align"/> 
     </xsl:attribute> 
    </xsl:if> 
    <xsl:for-each select="colspec"> 
     <th> 
     <xsl:if test="@colwidth"> 
      <xsl:attribute name="width"> 
      <xsl:value-of select="@colwidth"/> 
      </xsl:attribute> 
     </xsl:if> 
     <xsl:if test="@colname"> 
      <xsl:attribute name="colname"> 
      <xsl:value-of select="@colname"/> 
      </xsl:attribute> 
     </xsl:if> 
     <xsl:if test="@align"> 
      <xsl:attribute name="align"> 
      <xsl:value-of select="@align"/> 
      </xsl:attribute> 
     </xsl:if> 
     <xsl:if test="@colsep"> 
      <xsl:attribute name="colsep"> 
      <xsl:value-of select="@colsep"/> 
      </xsl:attribute> 
     </xsl:if> 
     <xsl:if test="@colnum"> 
      <xsl:attribute name="colnum"> 
      <xsl:value-of select="@colnum"/> 
      </xsl:attribute> 
     </xsl:if> 

     </th> 
    </xsl:for-each> 


</tr> 
<xsl:apply-templates/> 

그러나 같은 XSLT 파일에 위의 코드를 가진

<table bnf_id="bnf_204272" colsep="1" frame="all" id="nzf_3865" otherprops="HRT Risk table" pgwide="1" rowsep="1"><title>HRT Risk</title><tgroup cols="8" colsep="1" rowsep="1"><colspec colname="col1" /><colspec colname="col2" /><thead><row><entry morerows="1" rowsep="1">Risk</entry><entry morerows="1" rowsep="1">Age range (years)</entry><entry colsep="1" nameend="col4" namest="col3" rowsep="1">Background incidence per 1000 women in Europe not using HRT</entry><entry colsep="1" nameend="col6" namest="col5" rowsep="1"><b>Additional</b> 
        cases per 1000 women using 
        <b>oestrogen only HRT</b> 
        (estimated) 
       </entry><entry colsep="1" nameend="col8" namest="col7" rowsep="1"><b>Additional</b> 
        cases per 1000 women using 
        <b>combined (oestrogen-progestogen) HRT</b> 
        (estimated) 
       </entry></row><row><entry>Over 5 years</entry><entry nameend="col8" namest="col1"><b>Note</b><p>Where background incidence or additional cases have not been included in the table, this indicates a lack of available data. NS indicates a non-significant difference</p><p> 
        Taken from MHRA/CHM (<i>Drug Safety Update</i> 
        2007; 
        <b>1</b> 
        (2): 2–6) available at 
        <xref format="html" href="http://www.mhra.gov.uk/drugsafetyupdate"> 
         www.mhra.gov.uk/drugsafetyupdate 
        </xref></p></entry></row></tbody></tgroup></table> 

입니다 내 입력 파일입니다, 일에 대한 내 두 번째 경기가 실행됩니다. 그래서 내가

<th></th> 

같은 빈 차를 얻을하지만 난 태그 사이의 ...를 삽입해야합니다. 그것을 해결하는 방법?

Answer 1

xsl : if 조건을 닫는 전에 </th > 태그 앞에 추가하면 안됩니까?

<xsl:if test="@colnum"> 
     <xsl:attribute name="colnum"> 
      <xsl:value-of select="@colnum"/> 
     </xsl:attribute> 
    </xsl:if> 

    <xsl:if test="text() = ''"> 
     <xsl:text>...</xsl:text> 
    </xsl:if> 
</th>