2 차원 텍스트 구문 분석

Question

관련 정보가 비선형 방식으로 여러 줄로 퍼져있는 텍스트 파일을 구문 분석해야합니다. 예 :

1234 
1   IN THE SUPERIOR COURT OF THE STATE OF SOME STATE   
2    IN AND FOR THE COUNTY OF SOME COUNTY     
3      UNLIMITED JURISDICTION       
4       --o0o--         
5                  
6 JOHN SMITH AND JILL SMITH,  )        
             )        
7     Plaintiffs,  )        
             )        
8  vs.       )  No. 12345 
             )        
9 ACME CO, et al.,     )        
             )        
10     Defendants.  )        
    ___________________________________)        

나는 원고와 피고의 신원을 알아 내야합니다.

이 성적 증명서

은 formattings의 매우 다양한, 그래서 나는 항상 그 좋은 괄호가있는 믿을 수없는, 또는 원고와 피고 정보는 깔끔하게 오프 박스되고 예 :

1  SUPREME COURT OF THE STATE OF SOME OTHER STATE 
         COUNTY OF COUNTYVILLE 
2     First Judicial District 
        Important Litigation 
3 --------------------------------------------------X 
    THIS DOCUMENT APPLIES TO: 
4 
    JOHN SMITH, 
5       Plaintiff,   Index No. 
                2000-123 
6 
              DEPOSITION 
7     - against -    UNDER ORAL 
              EXAMINATION 
8            OF 
              JOHN SMITH, 
9           Volume I 

10 ACME CO, 
    et al, 
11       Defendants. 

12 --------------------------------------------------X 

두 상수는 다음과 같습니다

1. "원고는"같은 줄에 반드시 을 원고 (들)의 이름 뒤에 발생하지만하지 않습니다.
2. 원고 및 피고인의 이름은 이며 대문자입니다.

아이디어가 있으십니까?

Answer 1

나는 Martin's answer을 좋아한다.

import re 

# load file into memory 
# (if large files, provide some limit to how much of the file gets loaded) 
with open('paren.txt','r') as f: 
    paren = f.read() # example doc with parens 

# match all sequences of one or more alphanumeric (or underscore) characters 
# when followed by the word `Plaintiff`; this is intentionally general 
list_of_matches = re.findall(r'(\w+)(?=.*Plaintiff)', paren, 
    re.DOTALL|re.MULTILINE) 

# join the list separating by whitespace 
str_of_matches = ' '.join(list_of_matches) 

# split string by digits (line numbers) 
tokens = re.split(r'\d',str_of_matches) 

# plaintiffs will be in 2nd-to-last group 
plaintiff = tokens[-2].strip() 

테스트 : : 왼쪽에있는 숫자는 무엇

with open('paren.txt','r') as f: 
    paren = f.read() # example doc with parens 
list_of_matches = re.findall(r'(\w+)(?=.*Plaintiff)',paren, 
    re.DOTALL|re.MULTILINE) 
str_of_matches = ' '.join(list_of_matches)>>> tokens = re.split(r'\d', str_of_matches) 
tokens = re.split(r'\d', str_of_matches) 
plaintiff = tokens[-2].strip() 
plaintiff 
# prints 'JOHN SMITH and JILL SMITH' 

with open('no_paren.txt','r') as f: 
    no_paren = f.read() # example doc with no parens 
list_of_matches = re.findall(r'(\w+)(?=.*Plaintiff)',no_paren, 
    re.DOTALL|re.MULTILINE) 
str_of_matches = ' '.join(list_of_matches) 
tokens = re.split(r'\d', str_of_matches) 
plaintiff = tokens[-2].strip() 
plaintiff 
# prints 'JOHN SMITH'