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이 질문에 간단한 수정이 필요하고 매우 작습니다.C++ 2d 배열 클래스 함수 호출 도움말
나는 대학에서 C++의 두 번째 학기를 마쳤으며 방금 OOP에 들어갔다. 이것은 내 첫 OOP 프로그램이며, 그것은 나에게 약간의 문제를 일으키고있다. 다음은 내가받는 오류입니다.
Member function must be called or its address taken in function displayGrid(int,Cell (*)[20])
Member function must be called or its address taken in function Turn(int,int,Cell (*)[20])
Member function must be called or its address taken in function Turn(int,int,Cell (*)[20])
Warning: Parameter 'grid' is never used in function displayGrid(int,Cell (*)[20])
다음은 모두 내 코드입니다. 나는 그것이 필요한 것보다 훨씬 더 많은 코드임을 알고있다. 더 어렵게 만들면 유감스럽게 생각한다. 내가 실수로 뭔가를 삭제할 수 있다고 걱정했습니다.
const int MAX=20;
//Struct Cell holds player and their symbol.
class Cell
{
private:
int Player;
char Symbol;
public:
Cell(void);
void setPlayer(int);
void setSymbol(char);
int getPlayer(void);
char getSymbol(void);
};
Cell::Cell(void)
{
Symbol ='-';
}
void Cell::setPlayer(int player_num)
{
Player = player_num;
}
void Cell::setSymbol(char rps)
{
Symbol = rps;
}
int Cell::getPlayer(void)
{
return Player;
}
char Cell::getSymbol(void)
{
return Symbol;
}
void Turn(int, int, Cell[MAX][MAX]);
void displayGrid(int, Cell[MAX][MAX]);
void main(void)
{
int size;
cout << "How big would you like the grid to be: ";
cin >> size;
//Checks to see valid grid size
while(size>MAX || size<3)
{
cout << "Grid size must between 20 and 3." << endl;
cout << "Please re-enter the grid size: ";
cin >> size;
}
int cnt=1;
int full;
Cell grid[MAX][MAX];
//I use full to detect when the game is over by squaring size.
full = size*size;
cout << "Starting a new game." << endl;
//Exits loop when cnt reaches full.
while(cnt<full+1)
{
displayGrid(size, grid); //calls function to display grid
if(cnt%2==0) //if cnt is even then it's 2nd players turn
cout << "Player 2's turn." << endl;
else
cout << "Player 1's turn" << endl;
Turn(size, cnt, grid); //calls Turn do each players turn
cnt++;
}
cout << endl;
cout << "Board is full... Game Over" << endl;
}
void displayGrid(int size, Cell grid[MAX][MAX])
{
cout << endl;
cout << " ";
for(int x=1; x<size+1; x++) // prints first row
cout << setw(3) << x; // of numbers.
cout << endl;
//Nested-For prints the grid.
for(int i=1; i<size+1; i++)
{
cout << setw(2) << i;
for(int c=1; c<size+1; c++)
{
cout << setw(3) << grid[i][c].getSymbol;
}
cout << endl;
}
cout << endl;
}
void Turn(int size, int cnt, Cell grid[MAX][MAX])
{
char temp;
char choice;
int row=0;
int column=0;
cout << "Enter the Row: ";
cin >> row;
cout << "Enter the Column: ";
cin >> column;
//puts what is in the current cell in "temp"
temp = grid[row][column].getSymbol;
//Checks to see if temp is occupied or not
while(temp!='-')
{
cout << "Cell space is Occupied..." << endl;
cout << "Enter the Row: ";
cin >> row;
cout << "Enter the Column: ";
cin >> column;
temp = grid[row][column].getSymbol; //exits loop when finally correct
}
if(cnt%2==0) //if cnt is even then its player 2's turn
{
cout << "Enter your Symbol R, P, or S (Capitals): ";
cin >> choice;
grid[row][column].setPlayer(1);
in >> choice;
}
//officially sets choice to grid cell
grid[row][column].setSymbol(choice);
}
else //if cnt is odd then its player 1's turn
{
cout << "Enter your Symbol r, p, or s (Lower-Case): ";
cin >> choice;
grid[row][column].setPlayer(2);
//checks for valid input by user1
while(choice!= 'r' && choice!='p' && choice!='s')
{
cout << "Invalid Symbol... Please Re-Enter: ";
cin >> choice;
}
//officially sets choice to grid cell.
grid[row][column].setSymbol(choice);
}
cout << endl;
}
감사합니다.
그것은 도움이 될 것입니다 –