대출 계산기 변경

Question

대출을 계산하는 프로그램을 만들었지 만 교수가 요구 한 지침에 미치지 않습니다. 나에게 정확한 변경을 보여줄 수있다. 소스 코드는 멋지고 시간을 절약 할 수 있지만 꼭 할 필요는 없습니다.

을 Heres 문제 :

사용자가 년의 수에 대출 금액과 대출 기간을 입력 할 수 있습니다 5 %에서 8 %로 시작 각각의 이자율에 대한 월별 총 지불을 표시하는 프로그램을 작성, 1/8 씩 증가합니다. Heres는 샘플 실행 :

Loan amount: 10000 [Enter] 
Numbers of Years: 5: [Enter] 

Interest rate   Monthly Payment      Total Payment 
5%       188.71        11322.74 
5.125%      189.28        11357.13 

Heres는 내 앞의 코드 :

# include <iostream> 
# include <iomanip> 
# include <cmath> 

using namespace std; 

int main() 
{ 
    double loanAmountA; 
    double annualRate; 
    double paymentAmount; 
    double amountInterest; 
    double ratePeriod; 
    double balanceAfter; 
    double amountApplied; 
    double balance; 
    double paymentPeriod; 
    int paymentsPerYear; 
    int totalPayments; 
    int loanCount = 1; 
    int paymentCount = 1; 
    bool anotherLoan = true; 
    char response; 

    while (anotherLoan == true) 
    { 
     cout<<"Enter amount of loan A:$ "; 
     cin>>loanAmountA; 
     cout<<endl; 
     cout<<"Enter annual percentage rate (APR): "<<"%"; 
     cin>>annualRate; 
     cout<<endl; 
     cout<<"Enter the number of payments per year: "; 
     cin>>paymentsPerYear; 
     cout<<endl; 
     cout<<"Enter the total number of payments: "; 
     cin>>totalPayments; 
     cout<<endl; 
     cout<<"Payment Payment Amount Amount to Balance after"; 
     cout<<endl; 
     cout<<"Number Amount Interest Principal This Payment"; 
     cout<<endl; 

     cin.ignore(80,'\n'); 

     while (paymentCount <=totalPayments) 
     { 
      annualRate = annualRate/100; 
      balance = loanAmountA - totalPayments * paymentAmount; 
      ratePeriod = balance * annualRate; 
      paymentAmount = loanAmountA * (totalPayments/paymentsPerYear * annualRate)/totalPayments; 
      balanceAfter = balance - paymentAmount; 
      balance = loanAmountA - (paymentCount * paymentAmount); 


      cout<<left<<setprecision(0)<<setw(3)<<paymentCount; 
      cout<<setw(13)<<left<<fixed<<setprecision(2)<<paymentAmount; 
      cout<<setw(26)<<left<<fixed<<setprecision(2)<<ratePeriod; 
      cout<<setw(39)<<left<<fixed<<setprecision(2)<<balance; 
      cout<<setw(42)<<left<<fixed<<setprecision(2)<<balanceAfter; 

      if (paymentCount % 12 == 0) 
      { 
       cout<<endl; 
       cout<<"Hit <Enter> to continue: "<<endl; 
       cin.ignore(80,'\n'); 
       cin.get(); 
      } 
      paymentCount++; 
      loanCount++; 
      cout<<endl; 
     } 

     cout<<"Would you like to calculate another loan? y/n and <enter>"; 
     cin>>response; 
     if (response == 'n') 
     { 
      anotherLoan = false; 
      cout<<endl<<endl; 
      cout<<"There were"<<loanCount<< "loans processed."; 
      cout<<endl<<endl; 
     } 
    } 
    return 0; 
} 

Answer 1

디버거를 사용하고, 실패의 지점을 찾으려고 했습니까?