MongoDB를 사용하여 트랜잭션을 위해 JPA EntityManager를 열 수 없습니다.

Question

MongoDB에서 Spring, Hibernate-OGM을 사용하려고합니다. 그러나 거래 문제가 있습니다. 나는 그들이 MongoDB에 의해 지원되지 않는다는 것을 안다. 그러나 주석을 @transactional 사용하고 싶다. 그래서 나는 시작, 커밋을하지 않아도된다.

예외

org.springframework.transaction.CannotCreateTransactionException: Could not open JPA EntityManager for transaction; nested exception is java.lang.IllegalStateException: A JTA EntityManager cannot use getTransaction() 
at org.springframework.orm.jpa.JpaTransactionManager.doBegin(JpaTransactionManager.java:430) 
at org.springframework.transaction.support.AbstractPlatformTransactionManager.getTransaction(AbstractPlatformTransactionManager.java:373) 
at org.springframework.transaction.interceptor.TransactionAspectSupport.createTransactionIfNecessary(TransactionAspectSupport.java:420) 
at org.springframework.transaction.interceptor.TransactionAspectSupport.invokeWithinTransaction(TransactionAspectSupport.java:257) 
at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:95) 
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:179) 
at org.springframework.aop.framework.CglibAopProxy$DynamicAdvisedInterceptor.intercept(CglibAopProxy.java:644) 

DB의 context.xml에

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean"> 
    <property name="persistenceUnitName" value="mongo-hibernate"/>  
    </bean> 

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> 
    <property name="entityManagerFactory" ref="entityManagerFactory"/> 
    </bean> 

    <tx:annotation-driven transaction-manager="transactionManager"/> 

의 persistence.xml

<persistence-unit name="mongo-hibernate" transaction-type="JTA"> 
     <provider>org.hibernate.ogm.jpa.HibernateOgmPersistence</provider> 

     <properties> 
      <property name="hibernate.current_session_context_class" value="thread"/>       
      <property name="hibernate.ogm.datastore.provider" value="mongodb"/> 
      <property name="hibernate.ogm.datastore.grid_dialect" value="org.hibernate.ogm.datastore.mongodb.MongoDBDialect"/>   
      <property name="hibernate.transaction.factory_class" value="org.hibernate.transaction.JTATransactionFactory"/>     
      <property name="hibernate.ogm.datastore.database" value="mongodbtest"/> 
      <property name="hibernate.ogm.mongodb.database" value="mongodbtest"/> 
      <property name="hibernate.ogm.mongodb.host" value="localhost"/> 
      <property name="hibernate.ogm.mongodb.associations.store" value="IN_ENTITY"/> 
     </properties> 

    </persistence-unit> 
</persistence> 

DAO

@PersistenceContext 
protected EntityManager entityManager; 

@Transactional(readOnly = false) 
public <E> void updateObject(E entity) { 
    entityManager.persist(entity); 
} 

어떤 도움을 주시면 감사하겠습니다. 지금까지 내가 조금 더 이동하면

Answer 1

감사, 나는 일부 파일을 변경 :

DB의 context.xml에

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean"> 
    <property name="persistenceUnitName" value="mongo-hibernate"/>  
    </bean> 

    <bean class="com.arjuna.ats.jta.TransactionManager" factory-method="transactionManager" id="arjunaTransactionManager"/> 
    <bean class="com.arjuna.ats.jta.UserTransaction" factory-method="userTransaction" id="arjunaUserTransaction"/> 

    <bean id="transactionManager" class="org.springframework.transaction.jta.JtaTransactionManager"> 
    <property name="transactionManager" ref="arjunaTransactionManager"/> 
    <property name="userTransaction" ref="arjunaUserTransaction"/> 
    </bean> 

    <tx:annotation-driven transaction-manager="transactionManager"/> 

DAO :이 방법 eveything은 잘 작동

@PersistenceContext 
protected EntityManager entityManager; 

@Transactional(readOnly = false) 
public <E> void updateObject(E entity) { 

    Session session = entityManager.unwrap(Session.class);   
    org.hibernate.Transaction tx = session.getTransaction(); 
    tx.begin(); 
    session.persist(entity); 
    tx.commit(); 

} 

그러나 나는 다음과 같이 더 단순하게 작업하고 싶습니다.

@Transactional(readOnly = false) 
public <E> void updateObject(E entity) { 
    entityManager.persist(entity); 
} 

제안 사항이 있으십니까?

Answer 2

그래, 나는 제안이있다 : 문서를 읽는다. ;)

"MongoDB does not support transaction."

괴사가 죄송