PHP : POST 오류

Question

허용되지 않습니다 그것이 내가 다음과 같은 오류 얻을 데이터베이스에 양식 내용을 제출하려고하면 제가 아파치를 실행하는 드림위버 CC 2017 XAMPP의 v3.2.2을 사용하고 {"code":"MethodNotAllowedError","message":"POST is not allowed"}

및 윈도우 10에서 MySQL

HTML 양식 :

<form action="register.php" id="form1" name="form1" method="post"> 

및 register.php 내용은 다음과 같습니다

<?php 
$hostname_conn = "localhost"; 
$database_conn = "hotels"; 
$username_conn = "root"; 
$password_conn = ""; 
$conn = mysqli_connect($hostname_conn, $username_conn, $password_conn) or trigger_error(mysqli_error(),E_USER_ERROR); 

$db=mysqli_select_db($conn,$database_conn); 
$q1= "insert into users(username,email,password,number)values('$_POST[textfield]','$_POST[email]','$_POST[password]','$_POST[number]')"; 
$q2=mysqli_query($conn,$q1); 

if(mysqli_query($conn,$q1)) 
{ 
    $msg = 'User information saved successfully.'; 
} 
else 
{ 
    $msg = 'Error: We encountered an error while inserting the new record.'; 
} 
echo $msg; 
mysqli_close($conn); 
?> 

</body> 
</html> 

,

Answer 1

문제는 구문입니다. 어쨌든 좋은 습관을 사용해야합니다. PDO를 사용하여이 게시물 How can I prevent SQL injection in PHP?

$username = $_POST["textfield"]; //unsafe 
$username = mysql_real_escape_string($username); //safe 

$email = mysql_real_escape_string($_POST["email"]); 
$password = mysql_real_escape_string($_POST["password"]); 
$number = mysql_real_escape_string($_POST["number"]); 

$db=mysqli_select_db($conn,$database_conn); 
$q1= "insert into users(username,email,password,number)values('".$username ."','".$email."','".$password."','".$number."')"; 
$q2=mysqli_query($conn,$q1); 

Answer 2

을 확인합니다

 $servername = "localhost"; 
     $username = "root"; 
     $password = ""; 
     $dbname = "hotels"; 
     $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password); 
     $stmt = $conn->prepare("INSERT INTO users (username, email, password, number) 
     VALUES (:username, :email, :password, :number)"); 
     $stmt->bindParam(':username', $username); 
     $stmt->bindParam(':email', $email); 
     $stmt->bindParam(':password', $password); 
     $stmt->bindParam(':number', $number); 
     $username = $_POST['textfield']; 
     $email = $_POST['email']; 
     $password = $_POST['password']; 
     $number = $_POST['number']; 
     $stmt->execute();