트리를 XML로 디스터 리어 처리

Question

트리 구조로 만들려는 다음 XML 데이터가 있습니까?

<DATA> 
    <NODES> 
    <NODE> 
     <ID>1</ID> 
     <CONTENT>Foo</CONTENT> 
     <ChildrenIds> 
      <Child>2</Child> 
      <Child>3</Child> 
     </ChildrenIds> 
     <Level>1</Level> 
    </NODE> 
    <NODE> 
     <ID>2</ID> 
     <CONTENT>Foo</CONTENT> 
     <ChildrenIds> 
      <Child>4</Child>    
     </ChildrenIds> 
    </NODE> 
    <NODE> 
     <ID>3</ID> 
     <CONTENT>oo</CONTENT> 
     <ChildrenIds> 
     <Child>5</Child> 
     </ChildrenIds> 
    </NODE> 
    <NODE> 
     <ID>4</ID> 
     <CONTENT>Doo</CONTENT> 
     <ChildrenIds/> 
    </NODE> 
    <NODE> 
     <ID>5</ID> 
     <CONTENT>Koo</CONTENT> 
     <ChildrenIds/> 
    </NODE> 
    </NODES> 
</DATA> 

LINQ를 사용하여 이것을 트리 구조로 구문 분석하는 가장 좋은 방법은 무엇입니까?

내가 먼저 예를 들면 다음과 같이 트리 객체로 시작해야 겠지 :

public class Tree 
{ 
    public Tree() 
    { 
     ChildrenNodes = new List<TreeStructure>(); 
    } 

    public List<Tree> ChildrenNodes { get; set; } 
    public int Id { get; set; } 
    public string Content {get; set;} 
} 

Answer 1

usign system.runtime.serialization 

[datacontract] 
public class Tree 
{ 
    public Tree() 
    { 
     ChildrenNodes = new List<TreeStructure>(); 
    } 
    [datamember] 
    public List<Tree> ChildrenNodes { get; set; } 
    [datamember] 
    public int Id { get; set; } 
    [datamember] 
    public string Content {get; set;} 
} 

void serialize(Tree tree,string filename) 
{ 
datacontractserializer serializer = new datacontracetserializer (typeof(Tree)); 
system.xml.xmltextwriter writer = new xmltextwriter(filename,Encoding.UTF32); 
serializer.WriteObject(writer,tree); 
writer.close(); 
} 

void deserialize(ref Tree tree,string filename) 
{ 
    xmltextreader reader = new xmltextreader*new streamreader(filename, Encoding.UTF32)); 
DataContracetSerializer deser = new datacontracetserializer(typeof(Tree)); 
trr = (Tree)deserializer.readObject(reader); 
reader.close() 
} 

인코딩