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자습서를 따라 API에서 데이터를 가져 왔지만 현재 내 모델에서는 작동하지 않습니다. 목표는 무엇중첩 된 JSON 값 가져 오기
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}
,이 응답 내에서 "결과"를 얻을 수있는 그대로 모델은 할 수 있습니다 응답은 다음과 같이 중첩 된
List<Show> items = new Gson().fromJson(response.toString(), new TypeToken<List<Show>>() {
}.getType());
있지만 : 다음과 같이 데이터를 가져옵니다 이 들판을 가져 가라. 나는이 이름들의 대부분이 정의 된 간단한 Show 모델을 가지고있다. 나는 그것을 어디에서나 보지 못했지만, 단지 할 수있는 기능이 없다. List<Show> items = new Gson().fromJson(response.get("results").toString() ..) 또는 무엇인가? 참고 : 응답 구문 분석에 대해 읽었지 만, 위에서 언급 한 것처럼이 인덱스를 얻을 수있는 파이썬에 대해 더 잘 알고 있기 때문에 여기서도 가능한지 궁금합니다.
편집 : 더 많은 코드
private void fetch() {
JsonArrayRequest request = new JsonArrayRequest(URL,
response -> {
if (response == null) {
Toast.makeText(getApplicationContext(), "Couldn't fetch the menu! Pleas try again.", Toast.LENGTH_LONG).show();
return;
}
JsonArray results = new Gson().fromJson(response.toString(), JsonObject.class).getAsJsonArray("results");
List<Show> items = new Gson().fromJson(results, new TypeToken<List<Show>>() {}.getType());
showlist.clear();
showlist.addAll(items);
mAdapter.notifyDataSetChanged();
}, error -> {
Log.d(TAG, "Error: " + error.getMessage());
Toast.makeText(getApplicationContext(), "Error: " + error.getMessage(), Toast.LENGTH_SHORT).show();
});
TApplication.getInstance().addToRequestQueue(request);
}
'response.toString()'이 첨부 한 JSON을 반환하는지 100 % 확신합니까? 추가 중첩없이? 또한 사용중인 GSON 버전은 무엇입니까? 나는 가지고있다 : 'compile 'com.google.code.gson : gson : 2.8.2'' –
응답은 JSONArray (이것에 대해 Volley 라이브러리를 사용했다.) toJson에서 toString()을해야 할 것이다. , 거기에 JSONArray를 넣을 때 메서드를 해결할 수 없기 때문에 – dnsko
좋습니다.하지만 게시 한 JSON은 배열이 아닙니다. 이것은 개체입니다. 'response.toString()'이 반환하는 것을 붙여 넣을 수 있습니까? –