Java : 사용자에게 다시 재생할 것인지 묻습니다.

Question

나는 바위 종이 가위 게임을 만들고 컴퓨터 또는 사용자가 게임을 다시하고 싶다면 프롬프트를 보여줘야한다. "예"이면 프로그램이 다시 시작되고 "아니오"일 경우 system.exit을 추측합니다.

어떻게해야합니까?

public static void main(String[] args) { 
    Random r = new Random(); 
    int gameCount = 0; 
    int computerWins = 0; 
    int playerWins = 0; 
    int rock, paper, scissors; 
    rock = 1; 
    paper = 2; 
    scissors = 3; 
    int playerChoice = 0; 
    int computerChoice; 

    System.out.println("Welcome to Rock Paper Scissors! Best 2 out of 3!"); 

    //While the game count is less than 3, the loop will repeat 
    while (gameCount < 3) { 
     computerChoice = r.nextInt(3) + 1; 
     System.out.println("Enter \"Rock\", \"Paper\", or \"Scissors\""); 
     String USER_Input = userInput.next(); 
     if (USER_Input.equalsIgnoreCase("Rock")) { 
      playerChoice = 1; 
     } 
     if (USER_Input.equalsIgnoreCase("Paper")) { 
      playerChoice = 2; 
     } 
     if (USER_Input.equalsIgnoreCase("Scissors")) { 
      playerChoice = 3; 
     } 
     //If player enters anything besides rock, paper, or scissors 
     if (playerChoice <= 0 || playerChoice > 3) { 
      System.out.println("That wasn't an option"); 
      computerWins++; 
      gameCount++; 
      System.out.println("Not a valid input! Computer Wins!\n" + 
        "Player has won " +playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 

      //The game goes on, and the winners are added up! 
     } else if (playerChoice == 1 && computerChoice == 2) { 
      computerWins++; 
      gameCount++; 
      System.out.println("Rock v Paper! Computer Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 2 && computerChoice == 1) { 
      playerWins++; 
      gameCount++; 
      System.out.println("Paper v Rock! Player Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 2 && computerChoice == 3) { 
      computerWins++; 
      gameCount++; 
      System.out.println("Paper v Scissors! Computer Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 3 && computerChoice == 2) { 
      playerWins++; 
      gameCount++; 
      System.out.println("Scissors v Paper! Player Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 3 && computerChoice == 1) { 
      computerWins++; 
      gameCount++; 
      System.out.println("Scissors v Rock! Computer Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 1 && computerChoice == 3) { 
      playerWins++; 
      gameCount++; 
      System.out.println("Rock v Scissors! Player Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 1 && computerChoice == 1) { 
      gameCount++; 
      System.out.println("Rock v Rock! Tie!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 2 && computerChoice == 2) { 
      gameCount++; 
      System.out.println("Paper v Paper! Tie!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 3 && computerChoice == 3) { 
      gameCount++; 
      System.out.println("Paper v Paper! Tie!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } 

     //Check if game count reaches max games then chooses a winner 
     if (gameCount == 3 && computerWins > playerWins || computerWins == 2) { 
      System.out.println("The Computer Wins!"); 
      break; 
     } else if (gameCount == 3 && computerWins < playerWins || playerWins ==2) { 
      System.out.println("The Player Wins!"); 
     } else if (gameCount == 3 && computerWins == playerWins) { 
      System.out.println("The game is a tie!"); 
     } 
    } 
} 

Answer 1

전체 로직이 main() - 메소드 내에 있습니다. while() 부분을 play()와 같은 새로운 메서드로 옮기는 것이 좋습니다.

이

public static void main(String args[]) { 
     Scanner inputScanner = new Scanner(System.in); 
     String userInput = ""; 
     do { 
      play(); 
      System.out.print("Do you want to play again ([Y]/n)? "); 
      userInput = inputScanner.nextLine(); 
      System.out.println(userInput); 
     } while (userInput.equals("Y") || userInput.equals("")); 
} 

HTH, SiS는

Answer 2

가능한 솔루션에 게임을 배치하는 것입니다 : 주에서

() 메시지를 자극하고 키보드에서 입력을 읽는) (새로운 동안을 구현 다른 while 루프 (gameCount의 엔벨로프를 감싸는)와 while 루프 내에서 변수에 대한 switch 문을 작성하면 gameContinue이됩니다. 게임이 끝나면 사용자는 계속할지 여부를 묻는 메시지를 받게됩니다. 그들의 대답을 바탕으로 변수 gameContinue의 값을 변경하면됩니다.