MYSQL SELECT rank of user (x보다 작고 y보다 작음)

Question

나는 php/mysql 질의에 조금 갇혀있다. 나는이 같은 OUPUT 필요

table_users    table_ranks 
---------------- ------------------------ 
| id | points | | name | points_needed | 
---------------- ------------------------ 
| 1 | 2 | | lvl0 |  0  | 
| 2 | 10 | | lvl1 |  10  | 
| 3 | 21 | | lvl2 |  20  | 
| 4 | 29 | | lvl3 |  30  | 
---------------- ------------------------ 

: 나는 2 개 테이블을 가지고

• USER_1 = lvl0 (사용자가 2 점을 가지고 있기 때문에)
• User_2 = lvl1 (사용자가 10 점에 도달 단지 때문에)
• ...
• User_4 = lvl2

,536 (사용자가 아직 30 점에 도달하지 않았기 때문에)

당신을 생각하십시오 :)

감사합니다.

Answer 1

당신이

SELECT 
    tu.id, 
    tr.name, 
    tu.points 
FROM table_ranks as tr 
    LEFT JOIN (SELECT * FROM table_ranks LIMIT 1,69596585953484) as l 
    ON l.points_needed = (SELECT MIN(points_needed) FROM table_ranks WHERE points_needed > tr.points_needed limit 1) 
    LEFT OUTER JOIN table_users AS tu ON tu.points >= tr.points_needed AND tu.points < l.points_needed 
WHERE tu.id IS NOT NULL 
group by tu.id 

Fiddle

처럼 그것을 할 수 있습니다 제공

출력

------------------------- 
| id | points | name | 
------------------------- 
| 1 | lvl0 | 2 | 
| 2 | lvl1 | 10 | 
| 3 | lvl2 | 21 | 
| 4 | lvl2 | 29 | 
------------------------- 

Answer 2

이 시도 인해 테이블 ​​디자인에 지저분한 조금,

SELECT u.*, r.name 
FROM table_users u 
     INNER JOIN 
     (
      SELECT x.name, 
        x.points_needed start_point, 
        COALESCE(y.points_needed - 1, 2000000) end_point 
      FROM 
      (
       SELECT name, points_needed, @rank:=@rank+1 ranks 
       FROM table_ranks a, (SELECT @rank:=0) b 
       ORDER BY points_needed 
      ) x 
      LEFT JOIN 
      (
       SELECT name, points_needed, @rank1:=@rank1+1 ranks 
       FROM table_ranks a, (SELECT @rank1:=0) b 
       ORDER BY points_needed 
      ) y ON x.ranks+1 = y.ranks 
     ) r ON u.points BETWEEN r.start_point AND r.end_point 

• SQLFiddle Demo