2
의 TrueCrypt 파티션에있는 프로젝트에 대한 의욕과 함께 작동하는 동안 다음과 같이 나는 항상 오류 ko를 얻을 :Mercurial은 커밋/업데이트/등 중에 실패합니다. 사용 Mercuriual +의 TrueCrypt + MAC
** unknown exception encountered, details follow
** report bug details to http://mercurial.selenic.com/bts/
** or [email protected]
** Mercurial Distributed SCM (version 1.5.2+20100502)
** Extensions loaded:
Traceback (most recent call last):
File "/usr/local/bin/hg", line 27, in <module>
mercurial.dispatch.run()
File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 16, in run
sys.exit(dispatch(sys.argv[1:]))
File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 30, in dispatch
return _runcatch(u, args)
File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 50, in _runcatch
return _dispatch(ui, args)
File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 470, in _dispatch
return runcommand(lui, repo, cmd, fullargs, ui, options, d)
File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 340, in runcommand
ret = _runcommand(ui, options, cmd, d)
File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 521, in _runcommand
return checkargs()
File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 475, in checkargs
return cmdfunc()
File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 469, in <lambda>
d = lambda: util.checksignature(func)(ui, *args, **cmdoptions)
File "/Library/Python/2.6/site-packages/mercurial/util.py", line 401, in check
return func(*args, **kwargs)
File "/Library/Python/2.6/site-packages/mercurial/commands.py", line 3332, in update
return hg.update(repo, rev)
File "/Library/Python/2.6/site-packages/mercurial/hg.py", line 362, in update
stats = _merge.update(repo, node, False, False, None)
File "/Library/Python/2.6/site-packages/mercurial/merge.py", line 495, in update
_checkunknown(wc, p2)
File "/Library/Python/2.6/site-packages/mercurial/merge.py", line 77, in _checkunknown
for f in wctx.unknown():
File "/Library/Python/2.6/site-packages/mercurial/context.py", line 660, in unknown
return self._status[4]
File "/Library/Python/2.6/site-packages/mercurial/util.py", line 156, in __get__
result = self.func(obj)
File "/Library/Python/2.6/site-packages/mercurial/context.py", line 622, in _status
return self._repo.status(unknown=True)
File "/Library/Python/2.6/site-packages/mercurial/localrepo.py", line 1023, in status
if (f not in ctx1 or ctx2.flags(f) != ctx1.flags(f)
File "/Library/Python/2.6/site-packages/mercurial/context.py", line 694, in flags
flag = findflag(self._parents[0])
File "/Library/Python/2.6/site-packages/mercurial/context.py", line 690, in findflag
return ff(path)
File "/Library/Python/2.6/site-packages/mercurial/dirstate.py", line 145, in f
if 'x' in fallback(x):
TypeError: argument of type 'NoneType' is not iterable
그것은 프로젝트의 TrueCrypt에 위치하지 않을 경우 의욕이 완벽하게 작동 가치가 언급이다 분할.
구성 : 맥 OS X 10.6.3 의욕 분산 SCM (버전 1.5.2 + 20100502) 파이썬 2.6.5
이 나를 도울 수 당신이 관대 한 사람의 사람이 있나요? :)
음 ... TrueCrypt 파티션을 사용하지 않습니까? 이것이 관련이있다면 또한 몰라. 그러나 http://www.g-loaded.eu/2006/11/05/truecrypt-on-2618-kernels/. 숨기기 기능이 없는데 왜 암호화를 사용하고 있습니까? ;) – msw
숨길 것이 없습니까? 당신 회사의 코드베이스는 어떻습니까? 노트북을 잃어 버리면 수백만 달러의 손해가 발생할 수도 있습니다. Truecrypted : 0입니다. 코딩 프로젝트를 Truecrypting하면 비즈니스 환경에서 어리석은 양의 의미가 생깁니다. – Groxx