Ansible 사실

Question

을 파고 나는 각본 각 시스템에 대한 전체 JSON 표현을 반환

--- 
- hosts: all 
    gather_facts: True 
    tasks: 
    - action: debug msg="time = {{ ansible_date_time }}" 

있습니다. 내가 더 나는 단지 iso8601_basic_short 부분을

[root@pjux playbooks]# ansible --version 
ansible 2.1.1.0 
    config file = /etc/ansible/ansible.cfg 
    configured module search path = Default w/o overrides 

TASK [디버그]를 얻을 수 있도록 플레이 북에서 그 필터링하려면 어떻게 ********************* *********************************************

확인 : [10.99.97.222] => { "msg": "시간 = {u'weekday_number ': u'2', u'iso8601_basic_short ': u'20160906T182117', u'tz ': u'BST', u '주 번호': u'36 ', u'hour': u'18 ', u'year': u'2016 ', u'minute': u'21 ', u'tz_offset': u '+ 0100' u'month ': u'09', u'epoch ': u'1473182477', u'iso8601_micro ': u'2016-09-06T17 : 21 : 17.761900Z', u'weekday ': u'Tuesday', u '시간': u'18 : 21 : 17 ', u'date': u'2016-09-06 ', u'iso8601': u'2016-09-06T17 : 21 : 17Z ', u'day 'u'06'u'iso8601_basic 'u'20160906T182117761843'u'second 'u'17'} " }

확인 : 10.99.97.216] => { "MSG ":"시간 = {u'weekday_number ': u'2', u'iso8601_basic_short ': u'20160906T182117', u'tz ': u'BST', u'weeknumber ': u'36', u'hour ' : u'18 ', u'year': u'2016 ', u'minute': u'21 ', u'tz_offset': u '+ 0100', u'month ': u'09', u'epoch ': u'1473182477', u'iso8601_micro ': u'2016-09-06T17 : 21 : 17.938563Z', u'weekday ': u'Tuesday', u'time ': u'18 : 21 : 17', u'date ': u'2016-09-06', u'iso8601 ': u'2016-09-06T17 : 21 : 17Z', u'day ': u'06', u'iso8601_basic ': u'20160906T182117938491 ', u' second': u'17 '} " }

Answer 1

{{ ansible_date_time.iso8601_basic_short }}을 사용해 보셨습니까?