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XSLT를 사용하여 BBCode를 HTML로 변환하려고합니다. 그게 내가 무슨 짓을했는지 :XSLT를 사용하여 BBCode를 HTML로 변환
내가 무엇을 얻을<xsl:stylesheet exclude-result-prefixes="foo xslt" version="2.0" xmlns="http://www.w3.org/TR/xhtml1/strict"
xmlns:foo="urn:foo" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xslt="http://xml.apache.org/xslt">
<xsl:output encoding="UTF-8" indent="yes" media-type="text/html" method="html" version="4.0" xslt:indent-amount="4"/>
<xsl:function name="foo:bbcode-to-xhtml">
<xsl:param name="bbcode"/>
<xsl:analyze-string flags="is" regex="\[url=(.*?)\](.*?)\[/url\]" select="$bbcode">
<xsl:matching-substring>
<a href="{regex-group(1)}">
<xsl:value-of select="regex-group(2)"/>
</a>
</xsl:matching-substring>
<xsl:non-matching-substring>
<xsl:value-of select="."/>
</xsl:non-matching-substring>
</xsl:analyze-string>
</xsl:function>
<xsl:template match="/">
<xsl:value-of select="foo:bbcode-to-xhtml('A [url=http://www.example.com/]Foo[/url] of Bar!')"/>
</xsl:template>
</xsl:stylesheet>
:
A Foo of Bar!
그리고 내가 기대하는 것입니다 :
A <a href="http://www.example.com/">Foo</a> of Bar!
사람이 내가 잘못 무슨 말을 할 수 있습니까?
그게 전부 야! 이런! ;) – Michael