2011-08-04 6 views
1

다음 코드가 어떤 오류인지 사용자가 안내해 줄 수 있습니까? 고마워요!자바 스크립트 업로드 오류

$(document).ready(function() { 
    var uploader = new qq.FileUploader({ 
    // pass the dom node (ex. $(selector)[0] for jQuery users) 
    element: document.getElementById('file-uploader'), 
    // path to server-side upload script 
    action: '/static/upload/php.php', 
    onComplete: function(id, fileName, responseJSON){ 
     $('#form_upload').html(); 
     $('#form_upload').append('<input type="hidden" name="upload_file" value="'+fileName+'" />'); 
     $('#form_upload').append('<input type="hidden" name="upload_file_path" value="'+/IT1234/01/Week1+'" />'); 
     $('#form_upload').submit(); 
    } 
}); 

답변

0

번째 마지막 중괄호 (}는) 그 후 닫는 괄호 ())가 필요합니다. 또한 세미콜론 (;)을 입력해야합니다.

$(document).ready(function() { 
    var uploader = new qq.FileUploader({ 
    // pass the dom node (ex. $(selector)[0] for jQuery users) 
    element: document.getElementById('file-uploader'), 
    // path to server-side upload script 
    action: '/static/upload/php.php', 
    onComplete: function(id, fileName, responseJSON){ 
     $('#form_upload').html(); 
     $('#form_upload').append('<input type="hidden" name="upload_file" value="'+fileName+'" />'); 
     $('#form_upload').append('<input type="hidden" name="upload_file_path" value="'+/IT1234/01/Week1+'" />'); 
     $('#form_upload').submit(); 
    }); 
});