1
는jQuery replaceWith Flash 객체 매개 변수에?
<div id="dialog" style="display:none; width:100%; vertical-align:middle;">
<object id="player" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" name="player" width="628" height="400">
<param name="movie" value="../../help/videos/videoplayer.swf" />
<param name="allowfullscreen" value="true" />
<param name="allowscriptaccess" value="always" />
<param name="flashvars" value="file=../../help/videos/video.flv" />
<object type="application/x-shockwave-flash" data="../../help/videos/videoplayer.swf" width="628" height="400">
<param name="movie" value="../../help/videos/videoplayer.swf" />
<param name="allowfullscreen" value="true" />
<param name="allowscriptaccess" value="always" />
<param name="flashvars" value="file=../../help/videos/video.flv" />
</object>
</object>
왜 것 아닌
$("#dialog").find('<param name="flashvars" value="file=../../help/videos/video.flv" />').replaceWith('<param name="flashvars" value="file=../../help/videos/myfile.flv" />');
작업을 감안할 때? 당신은 찾을 수 선택기를 전달하지 않는
합니다. – Rio