XML 문서를 deserialize하려고하는데 사용하는 코드가 매번 Null 값을 반환합니다.XML 객체에 직렬화 해제하면 null 값이 반환됩니다.
나는이
<?xml version="1.0" encoding="utf-8"?>
<RegistrationOpenData xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://example.gov">
<Description>Registration data is collected by ABC XYZ</Description>
<InformationURL>http://www.example.com/html/hpd/property-reg-unit.shtml</InformationURL>
<SourceAgency>ABC Department of Housing</SourceAgency>
<SourceSystem>PREMISYS</SourceSystem>
<StartDate>2016-02-29T00:03:06.642772-05:00</StartDate>
<EndDate i:nil="true" />
<Registrations>
<Registration xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<RegistrationID>108260</RegistrationID>
<BuildingID>4731</BuildingID>
</Registration>
</Registrations>
</RegistrationOpenData>
같은 XML이 직렬화해야, I 클래스
using System.Xml.Serialization;
using System.Xml;
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(Namespace="http://example.gov")]
[System.Xml.Serialization.XmlRootAttribute(Namespace="http://example.gov", IsNullable=true)]
public partial class Registration : InfoClass {
private long registrationIDField;
private bool registrationIDFieldSpecified;
private System.Nullable<long> buildingIDField;
private bool buildingIDFieldSpecified;
public long RegistrationID
{
get
{
return this.registrationIDField;
}
set
{
this.registrationIDField = value;
}
}
[System.Xml.Serialization.XmlIgnoreAttribute()]
public bool RegistrationIDSpecified {
get {
return this.registrationIDFieldSpecified;
}
set {
this.registrationIDFieldSpecified = value;
}
}
[System.Xml.Serialization.XmlElementAttribute(IsNullable=true)]
public System.Nullable<long> BuildingID {
get {
return this.buildingIDField;
}
set {
this.buildingIDField = value;
}
}
[System.Xml.Serialization.XmlIgnoreAttribute()]
public bool BuildingIDSpecified {
get {
return this.buildingIDFieldSpecified;
}
set {
this.buildingIDFieldSpecified = value;
}
}
내가 사용하고있는 코드를 여기에
public void Test()
{
Registration RegistrationVal = null;
var xRoot = new XmlRootAttribute();
xRoot.ElementName = "RegistrationOpenData";
xRoot.Namespace = "http://services.hpd.gov";
xRoot.IsNullable = true;
var serializer = new XmlSerializer(typeof(Registration), xRoot);
using (TextReader reader = new StreamReader(@"D:\sample.xml"))
{
RegistrationVal = (Registration)serializer.Deserialize(reader);
}
}
가 있습니다 만든 항상 Null 값을 반환합니다. 미리 도움을 주셔서 감사합니다.
디버깅 할 때 예외가 표시됩니까? –
아니요, TextBox의 RegistrationID 값을 얻으려고했는데 0을 인쇄합니다 – Hanumendra
'InfoClass'에 어떤 코드가 있습니까? xml 속성이 있습니까? –