2013-03-29 2 views
2

사용자를 삭제하고 업데이트 할 수있는 사용자 관리 페이지가 있습니다. 닫기 창 옵션이있는 창을 팝업으로 표시하려면 사용자 페이지를 삭제하고 업데이트하고 싶습니다. 하지만 난 여기에 내 옴 사용자 코드PHP 페이지를 여는 팝업 창

<?php 
//MY PHP stuff 
?> 
<!DOCTYPE html PUBLIC “-//W3C//DTD XHTML 1.0 Strict//EN” 
“http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd”> 
<html xmlns=”http://www.w3.org/1999/xhtml”> 
<head> 
<meta http-equiv=”Content-Type” content=”text/html; charset=utf-8” /> 
<title>Manage Users</title> 
<link rel="stylesheet" type="text/css" href="../allcss/style.css" /> 
</head> 

<body> 

<?php 
require('../Login/includes/header.inc.php'); 
?> 

<div id="personalised"> 
<p>Hello, </p> 
</div> 
<div id="content"> 
<table> 
    <tr> 
    <th scope="col">User email</th> 
    <th scope="col">User name</th> 
    <th scope="col">User role</th> 
    <th>&nbsp;</th> 
    <th>&nbsp;</th> 
    </tr> 
    <?php while($row = $result ->fetch_assoc()) { ?> 
    <tr> 
    <td><?php echo $row['user_email']; ?></td> 
    <td><?php echo $row['user_name']; ?></td> 
    <td><?php echo $row['user_role']; ?></td> 
    <td><a href="update_users.php?person_id=<?php echo $row['person_id']; ?>">EDIT</a></td> 
    <td><a href="delete_users.php?person_id=<?php echo $row['person_id']; ?>">DELETE</a></td> 
    </tr> 
    <?php } ?> 
</table> 
</div> 


</body> 
</html> 

얼마나 모르겠어요 그리고 이것은

<?php 

require_once 'login.php'; 
$table="users"; 
$OK = false; 
$done = false; 
$conn = new mysqli ($host, $user, $password, $database) or die("Connection Failed"); 

$stmt= $conn->stmt_init(); 

if (isset($_GET['person_id']) && !$_POST) { 
    // prepare SQL query 
    $sql = 'SELECT person_id, user_email, user_name, user_role FROM users 
      WHERE person_id = ?'; 
    if ($stmt->prepare($sql)) 
    { 
    $stmt->bind_param('i', $_GET['person_id']); 
    $stmt->bind_result($person_id, $user_email, $user_name, $user_role); 
    $OK = $stmt->execute(); 
    $stmt->fetch(); 
    $_SESSION['uemail_update'] = $user_email; //new 
    } 
} 
if (isset($_POST ['update'])) { 
    // prepare update query 
    $sql = 'UPDATE users SET user_name = ?, user_role = ? 
      WHERE person_id = ?'; 
    if ($stmt->prepare($sql)) { 
    $stmt->bind_param('ssi', $_POST['user_name'], $_POST['user_role'], $_POST['person_id']); 
    $done = $stmt->execute(); 
    } 
} 
// redirect if $_GET['aperson_id'] not defined 
if ($done) { 
    header('Location: update_users_confirm.php'); 
    exit; 
} 
if (!isset($_GET['person_id'])) { 
    header("Location: manage_users.php"); 
    exit; 
} 
// store error message if query fails 
if (isset($stmt) && !$OK && !$done) { 
    $error = $stmt->error; 
} 
?> 
<!DOCTYPE html PUBLIC “-//W3C//DTD XHTML 1.0 Strict//EN” 
“http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd”> 
<html xmlns=”http://www.w3.org/1999/xhtml”> 
<head> 
<meta http-equiv=”Content-Type” content=”text/html; charset=utf-8” /> 
<title>Project Confirmation</title> 
<link rel="stylesheet" type="text/css" href="../allcss/style.css" /> 
</head> 

<body> 

<?php 
require('../Login/includes/header.inc.php'); 
?> 

<div id="personalised"> 
<p>Hello, </p> 
</div> 
<div id="content"> 
<?php 
if (isset($error)) { 
    echo "<p class='warning'>Error: $error</p>"; 
} 
if($person_id == 0) { ?> 
    <p class="warning">Invalid request: user does not exist.</p> 
<?php } else { ?> 
<form id="form1" method="post" action=""> 
    <p> 
    <label for="user_name">User name:</label> 
    <input name="user_name" type="text" class="widebox" id="user_name" value="<?php echo htmlentities($user_name, ENT_COMPAT, 'utf-8'); ?>"> 
    </p> 
    <p> 
    User role: <select name="user_role" size="1" id="user_role"> 
    <option value="PT">Part timer</option> 
    <option value="FT">Full timer</option> 
    <?php echo htmlentities($user_role, ENT_COMPAT, 'utf-8'); ?></select> 
    </p> 
    <p> 
    <input type="submit" name="update" value="Update Entry" id="update"> 
    <input name="person_id" type="hidden" value="<?php echo $person_id; ?>"> 
    </p> 
</form> 
<?php } ?> 
</div> 



</body> 
</html> 

것은 누군가에 나타나는 update_user.php 페이지를 만들기 위해 저를 도와 주실 수있는 update_user.php 페이지입니다 팝업 창이 나타나면 confirm.php 페이지가 표시됩니다.

감사

답변

5

당신은 JavaScript에 의해 그것을 할 수있는이 솔루션은 아래를 참조하십시오 :

머리 부분에 페이지의 상단에이 스크립트를 추가하는 것은

<script> 
function pop_up(url){ 
window.open(url,'win2','status=no,toolbar=no,scrollbars=yes,titlebar=no,menubar=no,resizable=yes,width=1076,height=768,directories=no,location=no') 
} 
</script> 

코드에 이러한 라인을 교체

<td> 
    <a href="update_users.php?person_id=<?php echo $row['person_id']; ?>" onclick="pop_up(this);">EDIT</a> 
</td> 
<td> 
    <a href="delete_users.php?person_id=<?php echo $row['person_id']; ?>" onclick="pop_up(this);">DELETE</a> 
</td> 

희망이 도움이 될 것입니다.

1

를 사용하여 자바 스크립트 기능.

function popupCenter(pageURL, title, w, h) { 
    var left = (screen.width/2) - (w/2); 
    var top = (screen.height/2) - (h/2); 
    var targetWin = window.open(pageURL, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=yes, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left); 
} 

<a href="#" onclick="popupCenter('delete_users.php?person_id=<?php echo $row['person_id']; ?>')">DELETE</a> 
+0