json invalid label?

Question

jsonlint를 통해이 json 파일을 실행했으며 유효한 것으로 돌아 왔지만 jquery에서이 파일을 사용하려고하면 "placemark"가 잘못된 라벨이라는 메시지가 나타납니다. 나 뭐 잘못 했니?

여기 내 JSON의 :

이

{ 
    "placemark": [ 
     { 
      "name": "Rosslyn Farms", 
      "path": "M -80.098181,40.42127 -80.096479,40.421262 -80.096464,40.421409 -80.096448,40.421551 -80.096444,40.421583 -80.096434,40.421666 -80.096406,40.421931 -80.096389,40.422087 -80.096353,40.422423 -80.09583,40.426101 -80.095525,40.428234 -80.095315,40.429714 -80.095276,40.429989 -80.092585,40.428593 -80.092273,40.428431 -80.09069,40.430519 -80.090384,40.430924 -80.08989,40.430618 -80.089699,40.4305 -80.089499,40.430359 -80.088738,40.429886 -80.088418,40.429688 -80.088254,40.429585 -80.087931,40.429384 -80.087086,40.428859 -80.086867,40.428722 -80.086658,40.428592 -80.086493,40.42849 -80.08617,40.428282 -80.086177,40.428265 -80.08621,40.428188 -80.0864,40.427742 -80.086397,40.42749 -80.086394,40.427125 -80.08631,40.426427 -80.086335,40.425887 -80.086235,40.425409 -80.085776,40.425327 -80.085442,40.42527 -80.084993,40.424585 -80.085076,40.42448 -80.085542,40.423842 -80.085679,40.423125 -80.085659,40.423011 -80.085626,40.422827 -80.085191,40.421758 -80.08467,40.420859 -80.084258,40.420336 -80.083828,40.4201 -80.083078,40.420005 -80.082504,40.420072 -80.081444,40.420196 -80.080888,40.420181 -80.080775,40.420178 -80.080604,40.420173 -80.080122,40.420161 -80.079753,40.420151 -80.07947,40.420144 -80.079287,40.420139 -80.078239,40.420296 -80.077661,40.420418 -80.076213,40.420726 -80.075673,40.420766 -80.075298,40.420719 -80.075127,40.420625 -80.074909,40.420307 -80.075028,40.419779 -80.07539,40.419028 -80.07583,40.41836 -80.076065,40.418108 -80.076528,40.417616 -80.077217,40.417124 -80.077503,40.417002 -80.077725,40.416907 -80.078391,40.416622 -80.078614,40.416528 -80.078657,40.41651 -80.078693,40.416491 -80.078755,40.416457 -80.079174,40.416233 -80.079205,40.416217 -80.079292,40.416128 -80.079439,40.415977 -80.079456,40.41596 -80.079614,40.415473 -80.079604,40.415377 -80.079584,40.415179 -80.07958,40.415168 -80.079539,40.415042 -80.079499,40.414915 -80.079407,40.414785 -80.079742,40.414965 -80.08086,40.415568 -80.081458,40.415889 -80.081535,40.41593 -80.082292,40.416343 -80.08238,40.416392 -80.082597,40.41651 -80.082624,40.416525 -80.082787,40.416614 -80.083508,40.417007 -80.083934,40.417239 -80.084422,40.417505 -80.084622,40.417432 -80.084852,40.417348 -80.085329,40.417179 -80.085419,40.417141 -80.085948,40.41695 -80.086252,40.417184 -80.088463,40.418885 -80.088964,40.418631 -80.089036,40.418595 -80.089145,40.418539 -80.089173,40.418525 -80.089346,40.418438 -80.089376,40.418457 -80.089398,40.418471 -80.089964,40.418827 -80.090299,40.419055 -80.091306,40.419739 -80.091642,40.419967 -80.091803,40.420088 -80.091966,40.420043 -80.092445,40.419915 -80.092561,40.419885 -80.096792,40.418748 -80.098853,40.41815 -80.098868,40.418242 -80.09943,40.421273 -80.098181,40.42127" 
     } 
    ] 
} 

여기 내 코드입니다 :

$(document).ready(function(){ 

    center=new google.maps.LatLng(mapLat, mapLong) 
    map = new google.maps.Map(document.getElementById('map'), { 
     center: center, 
     zoom: mapZoom, 
     mapTypeId: 'terrain' 

    }); 

    parseKML(); 




}); 

function parseKML() { 
    console.log(placemark.length); 

} 

Answer 1

나는 당신이 당신의 JSON 파일을 검색하지 않기 때문에 변수 장소는 여기에 정의라고 생각합니다.

당신은 아마 같은 것을해야합니다 (JSON 파일을 가정의 이름은 placemark.json) : 변수에

function parseKML() { 
    $.getJSON('placemark.json', function(data) { 
     console.log(data.placemark.length); 
    }); 
}