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Java에서 SAX XML Parser를 쓰려고하는데 해결 방법을 찾을 수없는 널 포인터 예외가 계속 발생합니다. 여기SAX XML Parser throw Null 포인터 예외
Exception in thread "main" java.lang.NullPointerException
at SAXParserExample.endElement(SAXParserExample.java:91)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.endElement(Unknown Source)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanEndElement(Unknown Source)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(Unknown Source)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(Unknown Source)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(Unknown Source)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(Unknown Source)
at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl$JAXPSAXParser.parse(Unknown Source)
at javax.xml.parsers.SAXParser.parse(Unknown Source)
at javax.xml.parsers.SAXParser.parse(Unknown Source)
at SAXParserExample.parseDocument(SAXParserExample.java:43)
at SAXParserExample.runExample(SAXParserExample.java:29)
at SAXParserExample.main(SAXParserExample.java:107)
SAX 파서의 주요 클래스입니다 : 여기
import java.io.IOException;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;
public class SAXParserExample extends DefaultHandler{
List<DataRow> myFiles;
private String tempVal;
//to maintain context
private DataRow tempFile;
public SAXParserExample(){
myFiles = new ArrayList<DataRow>();
}
public void runExample() {
parseDocument();
printData();
}
private void parseDocument() {
//get a factory
SAXParserFactory spf = SAXParserFactory.newInstance();
try {
//get a new instance of parser
SAXParser sp = spf.newSAXParser();
//parse the file and also register this class for call backs
sp.parse("./src/filelist.xml", this);
}catch(SAXException se) {
se.printStackTrace();
}catch(ParserConfigurationException pce) {
pce.printStackTrace();
}catch(IOException ie) {
ie.printStackTrace();
}
}
/**
* Iterate through the list and print
* the contents
*/
private void printData(){
System.out.println("No of Files '" + myFiles.size() + "'.");
Iterator<DataRow> it = myFiles.iterator();
while(it.hasNext()) {
System.out.println(it.next().toString());
}
}
//Event Handlers
public void startElement(String uri, String localName, String qName) throws SAXException {
//reset
tempVal = "";
if(qName.equalsIgnoreCase("DATAROW")) {
//create a new instance of Datarow
tempFile = new DataRow();
}
}
public void characters(char[] ch, int start, int length) throws SAXException {
tempVal = new String(ch,start,length);
}
public void endElement(String uri, String localName, String qName) throws SAXException {
if(qName.equalsIgnoreCase("DATAROW")) {
//add it to the list
myFiles.add(tempFile);
}else if (qName.equalsIgnoreCase("ID")) {
tempFile.setID(Integer.parseInt(tempVal));
}else if (qName.equalsIgnoreCase("FILENAME")) {
tempFile.setFileName(tempVal);
}else if (qName.equalsIgnoreCase("SEARCHKEY")) {
tempFile.setSearchKey(tempVal);
}else if (qName.equalsIgnoreCase("DATEADDED")) {
tempFile.setDateAdded(tempVal);
}else if (qName.equalsIgnoreCase("APPLICATIONID")) {
tempFile.setApplicationID(tempVal);
}else if (qName.equalsIgnoreCase("DISPLAYFILENAME")) {
tempFile.setDisplayFileName(tempVal);
}
}
public static void main(String[] args){
SAXParserExample spe = new SAXParserExample();
spe.runExample();
}
}
는 메인 클래스에 사용 된 DataRow 클래스입니다 : 여기
public class DataRow {
private String fileName = "", searchKey = "", dateAdded = "", applicationID = "", displayFileName = "";
private int id = 0;
public DataRow(){
}
public DataRow(int id, String fileName, String searchKey, String dateAdded, String applicationID, String displayFileName) {
this.id = id;
this.fileName = fileName;
this.searchKey = searchKey;
this.dateAdded = dateAdded;
this.applicationID = applicationID;
this.displayFileName = displayFileName;
}
public String getFileName() {
return fileName;
}
public void setFileName(String fileName) {
this.fileName = fileName;
}
public int getID() {
return id;
}
public void setID(int id) {
this.id = id;
}
public String getSearchKey() {
return searchKey;
}
public void setSearchKey(String searchKey) {
this.searchKey = searchKey;
}
public String getDateAdded() {
return dateAdded;
}
public void setDateAdded(String dateAdded) {
this.dateAdded = dateAdded;
}
public String getApplicationID() {
return applicationID;
}
public void setApplicationID(String applicationID) {
this.applicationID = applicationID;
}
public String getDisplayFileName() {
return displayFileName;
}
public void setDisplayFileName(String displayFileName) {
this.displayFileName = displayFileName;
}
public String toString() {
StringBuffer sb = new StringBuffer();
sb.append("File Details - ");
sb.append("ID:" + getID());
sb.append(", ");
sb.append("Filename:" + getFileName());
sb.append(", ");
sb.append("Search Key:" + getSearchKey());
sb.append(", ");
sb.append("Date Added:" + getDateAdded());
sb.append(", ");
sb.append("Application ID:" + getApplicationID());
sb.append(", ");
sb.append("Display Filename:" + getDisplayFileName());
sb.append(".");
return sb.toString();
}
}
그리고 여기에 스택 추적입니다 구문 분석하려고하는 XML 파일입니다.
<DATAROW><ID>61</ID><FILENAME>TestFile.txt</FILENAME><SEARCHKEY>12345</SEARCHKEY><DATEADDED>2012-1-6 9.12.32.0</DATEADDED><APPLICATIONID>PCIS</APPLICATIONID><DISPLAYFILENAME>TestFile.txt</DISPLAYFILENAME></DATAROW><DATAROW><ID>44</ID><FILENAME>TestFile.txt</FILENAME><SEARCHKEY>12345</SEARCHKEY><DATEADDED>2012-2-5 14.39.50.0</DATEADDED><APPLICATIONID>PCIS</APPLICATIONID><DISPLAYFILENAME>TestFile.txt</DISPLAYFILENAME></DATAROW>
XML 파일은 최종적으로 단일 문자열 형태로 데이터베이스에서 메타 데이터를 파싱 할 것이므로 형식이 지정됩니다.
어느 하나가 91입니다 잘 작동으로
변화를해야 하는가? – Tudor