Python 놈의 비트이며 내 코드에 정규 표현식을 추가해야하지만 제대로 작동하지 않습니다./Google에서 오류 메시지를 검색했습니다. 틀린. 그러나 행운이 아닌 것을 계산하려고 노력했다. 그래서 나는 그 다음으로 할 일이 직접적으로 물을 것이라고 생각했다. 그래서 num()
이 유효,TypeError : 'int'객체를 호출 할 수 없습니다. Python
# allows us to access a random 'key' in the dictionary
import random
import re
# Contains the question and it's correct answer
my_dict = {
"A form of Protectionism that imposes a tax on imports" : "tariff",
"....is quantity of a good or service that consumers are willing and able to buy at a given price in a given time period" : "Demand",
"....is the quantity of a good or service that a producer is willing and able to supply onto the market at a given price in a given time period" : "Supply",
"By using ..... businesses can bring down their average costs by producing on a larger scale" : "Economies of scale",
"The cost of the next best alternative" : "Opportunity Cost",
".... is the transfer of assets from the public (government) sector to the private sector." : "Privatisation"
}
# welcome message
print("Economics Revision App")
print("=======================")
# the quiz will end when this variable becomes 'False'
playing = True
# While the game is running
while playing == True:
# set the score to 0
score = 0
# gets the number of questions the player wants to answer
num = int(input("\nHow many questions would you like: "))
num = re.match("r\d[0-9]{2}$", num())
if match:
print ('foo')
# loop the correct number of times
for i in range(num):
# the question is one of the dictionary keys, picked at random
question = (random.choice(list(my_dict.keys())))
# the answer is the string mapped to the question key
answer = my_dict[question]
# print the question, along with the question number
print("\nQuestion " + str(i+1))
print(question + "?")
# get the user's answer attempt
guess = input("> ")
# if their guess is the same as the answer
if guess.lower() == answer.lower():
# add 1 to the score and print a message
print("Correct!")
score += 1
else:
print("Incorrect guess again!")
# after the quiz, print their final score
print("\nYour final score was " + str(score))
# store the user's input...
again = input("Enter any key to play again, or 'q' to quit.")
#... and quit if they types 'q'
if again.lower() == 'q':
playing = False
코드 나는 사투를 벌인거야 질문
에
다음으로 가장 좋은 것은 예외의 스택 추적에서 오류가 발생한 행을 확인하는 것입니다. 'num()'이'num = re.match ("r \ d [0-9] {2} $", num())'줄에 무엇을 의미한다고 생각합니까? –