시도해 볼 수 있습니다.
string xml = @"<Students>
<Student ID=""100"">
<Name>Arul</Name>
<Mark>90</Mark>
</Student>
<Student>
<Name>Arul2</Name>
<Mark>80</Mark>
</Student>
</Students>";
dynamic students = DynamicXml.Parse(xml);
var id = students.Student[0].ID;
var name1 = students.Student[1].Name;
foreach(var std in students.Student)
{
Console.WriteLine(std.Mark);
}
public class DynamicXml : DynamicObject
{
XElement _root;
private DynamicXml(XElement root)
{
_root = root;
}
public static DynamicXml Parse(string xmlString)
{
return new DynamicXml(XDocument.Parse(xmlString).Root);
}
public static DynamicXml Load(string filename)
{
return new DynamicXml(XDocument.Load(filename).Root);
}
public override bool TryGetMember(GetMemberBinder binder, out object result)
{
result = null;
var att = _root.Attribute(binder.Name);
if (att != null)
{
result = att.Value;
return true;
}
var nodes = _root.Elements(binder.Name);
if (nodes.Count() > 1)
{
result = nodes.Select(n => n.HasElements ? (object)new DynamicXml(n) : n.Value).ToList();
return true;
}
var node = _root.Element(binder.Name);
if (node != null)
{
result = node.HasElements || node.HasAttributes ? (object)new DynamicXml(node) : node.Value;
return true;
}
return true;
}
}
왜 당신은 그것을 시도하지? –
나는 던져 예외를 던지려고했지만 Json에서 작동하는 동일한 논리가 왜 XML을 지원하지 않는가? – user1875919
[XML을 동적 C# 객체로 변환] 가능한 복제본 (https://stackoverflow.com/questions/13171525/converting-xml-to- a-dynamic-c-sharp-object) –