클래스를 사용하여 데이터베이스에 삽입

Question

내가 뭘 잘못하고 있니?

오류 :

mysql_query() expects parameter 2 to be resource, string given in <b>php_includes/subscribers.php</b> on line <b>11</b><br /> 

<b>Warning</b>: mysql_query() expects parameter 2 to be resource, string given php_includes/comments.php</b> on line <b>19</b><br /> 

{"user":null,"comment":null,"error":true,"Comment":null} 

코드 :

<?php 

if(isset($_POST['task'])&& $_POST['task']=='comment_insert'){ 
    require_once("php_includes/db_conx.php"); 
    $userName= $_POST['userName']; 
    $userId=(int)$_POST['userId']; 
    $comment=addslashes(str_replace("\n" , "<br>" , $_POST['comment'])); 
    $std= new stdClass(); 
    $std->user=null; 
    $std->comment=null; 
    $std->error=false; 
    require_once("comments.php"); 

    if(class_exists('Comments') && class_exists('Subscribers')) 
    { 
     $userInfo = Subscribers::getSubscriber($userId); 
     if($userId == null) 

     { 
     $std->error=true; 
     } 

     $commentInfo = comments ::insert ($comment,$userId); 
     if($commentInfo == null) 
     {  
     $std->error=true; 
     } 

     $std -> user = $userInfo; 
     $std -> Comment = $commentInfo; 


     } 

    echo json_encode($std);  

    } 

    else{ 

     header('location:/jobs_article.php'); 
     } 

    ?> 


    /////////////////////////////////subscribers.php////////////////////// 

<?php 
require_once("comments.php"); 

    class Subscribers{ 
    public static function getSubscriber($userId){ 
    require_once("db_conx.php"); 

    $sql = " select * from users where id = $userId"; 
    $query = mysql_query($db_conx,$sql); 

    if($query){ 
     if(mysql_num_rows ($query)==1) 

    { 
    return mysql_fetch_object($query); 
    } 

    } return null; 

    } 

}?> 
    /////////////////////////////////end of subscribers.php////////////////////// 



///////////////////////////////////////////comments.php//////////////////////////// 

<?php 
    require_once("db_conx.php"); 
    require_once("subscribers.php"); 

    class Comments { 
    public static function getComments($userId){ 
    //return a stdclass object from the database 
} 


    public static function insert($userId){  
    $comment=addslashes($comment); 
    $sql= "INSERT into job_article_comments VALUES('' , '$comment' , '$userId')"; 
    $query=mysql_query($db_conx,$sql); 


     if($query){     
      $insert_id = mysql_insert_id(); 
      $std = new stdClass(); 
      $std->comment_id = $insert_id; 
      $std->comment = $comment; 
      $std->userId = $userId; 
      return $std; 
     } 

    return null; 

} 



    }?>///////////////// ///end of comment.php//////////////// 

Answer 1

귀하의 매개 변수를 거꾸로입니다. SQL 쿼리는 첫 번째 매개 변수는 DB 리소스는 두 번째입니다

$query = mysql_query($db_conx,$sql); 

이는 mysql_query 기능의

$query = mysql_query($sql, $db_conx); 

Answer 2

읽기 문서해야하며, 당신이 잘못하고있는 것을 볼 수 있습니다.

http://www.php.net/manual/en/function.mysql-query.php

참고 : 태그 한 것처럼 당신은 MySQL과하지 MySQLi를 사용하고 있습니다.