자바는 HSQLDB

Question

자바의 SQL 삽입을 수행하려고하지만, 불가능 HSQLDB에 커밋 커밋 :

public class VehiculeDAO extends DAO<Vehicule> { 

    public Vehicule create(int marque, int moteur, int prix, String nom) { 

     System.out.println("\t marque:" + marque +"moteur:"+moteur+"prix:"+prix+"nom:"+nom); 

     Vehicule vehicule = new Vehicule(); 

     String query = " INSERT INTO VEHICULE (MARQUE, MOTEUR, PRIX, NOM) VALUES (0,4,100,'test2');"; 
     query += "commit;"; 

     try { 
      connect.setAutoCommit(true); 
      ResultSet result = this.connect.createStatement(
      ResultSet.TYPE_SCROLL_INSENSITIVE, 
      ResultSet.CONCUR_UPDATABLE).executeQuery(" INSERT INTO VEHICULE (MARQUE, MOTEUR, PRIX, NOM) VALUES (0,4,100,'test3')"); 
      connect.commit(); 
      result.close(); 
     } catch (SQLException e) { 
      e.printStackTrace(); 
     } 
     //return; 
     return vehicule; 
    } 

삽입이 완료 되었으나 확정되지 않습니다. 디버깅에 대한 아이디어가 있으십니까?

어플리케이션의 간략한 설명 요청한 같이

HsqldbConnection :

public class HsqldbConnection { 

    private HsqldbConnection() { 
     try { 
      connect = DriverManager.getConnection(url, user, passwd); 

     } catch (SQLException e) { 
      e.printStackTrace(); 
     } 
    } 
    // ... 

TestDAO :

public class TestDAO { 

    public static void main(String[] args) throws SQLException { 
     DAO<Vehicule> vehiculedao = DAOFactory.getVehiculeDAO(); 
     Vehicule vehicule = vehiculedao.create(0 ,5, 100, "test"); 

     // ... 

DAOFactory

:

public class DAOFactory { 
    protected static final Connection conn = HsqldbConnection.getInstance(); 

    public static DAO getMarqueDAO(){ 
     return new MarqueDAO(conn); 
    } 

    public static DAO getVehiculeAO(){ 
     return new MarqueDAO(conn); 
    } 
} 

커밋 명령을 VehiculeDAO 클래스에 삽입해야합니다.

Test commit : 공공 정적 무효 메인 (문자열 []에 args) { 시도 {

String url = "jdbc:hsqldb:file:hsqldb/database/VEHICULE"; 
    String user = ""; 
    String passwd = ""; 

    Connection conn = DriverManager.getConnection(url, user, passwd); 

    Statement state = conn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_UPDATABLE); 
    PreparedStatement prepare = conn.prepareStatement("INSERT INTO VEHICULE (MARQUE, MOTEUR, PRIX, NOM) VALUES (0,4,100,'testcommit')"); 


    prepare.executeUpdate(); 

    conn.commit(); 

    prepare.close(); 

    state.close();   
} catch (SQLException e) { 
    e.printStackTrace(); 
}  

}

Answer 1

사용 statement.executeUpdate() 대신 statement.executeQuery().