XML 파일 [attributes]을 읽으려고합니다

Question

이 XML은 아래에 있습니다 : 어떻게 이것을 역 직렬화 할 수 있습니까? 이미 데이터 세트를 사용하고 속성을 가져 왔습니다.

<?xml version="1.0" encoding="UTF-8"?> 
<Result xmlns="urn:buscape" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" totalLooseOffers="0" schk="true" page="1" totalPages="1" totalResultsSellers="2" totalResultsReturned="2" totalResultsAvailable="2" xsi:schemaLocation="http://developer.buscape.com/admin/buscape.xsd"> 
    <details> 
     <applicationID>3833764c71496937647a773d</applicationID> 
     <date>2013-06-21T15:03:08.887-03:00</date> 
     <elapsedTime>450</elapsedTime> 
     <status>success</status> 
     <code>0</code> 
     <message>success</message> 
    </details> 
    <category concatenateCategoryName="false" hasOffer="true" isFinal="true" parentCategoryId="0" id="2921"> 
     <thumbnail url="http://imagem.buscape.com.br/bp5/categorias/2921.jpg" /> 
     <links> 
      <link type="category" url="http://compare.buscape.com.br/cds.html?mdsrc=9262544&amp;mdapp=4657&amp;mddtn=51922611" /> 
      <link type="xml" url="http://sandbox.buscape.com/service/findOfferList/3833764c71496937647a773d/br/?categoryId=2921&amp;keyword=thalles+roberto&amp;sourceId=9262544" /> 
     </links> 
     <name>CDs</name> 
    </category> 
    <offer id="119167238" categoryId="2921"> 
     <offerName>Uma História Escrita Pelo Dedo de Deus - Vol. 1 - Digipack - Thalles Roberto - Cod: 4049084 (CD)</offerName> 
     <offerShortName>Uma História</offerShortName> 
     <links> 
      <link type="offer" url="http://tracker.lomadee.com/tr/rd?b=amUMaQoBZRo4Jz8HbB9rPQQmLDcoZxoRCwE0Gzlzc2VnbGhsa2pqZWpoa2lla29nbGxob29lNioqLmRxcT0xMy4_LDtwPCstPT8uO3A9MTNwPCxxLiwxPQErMDc9MWE3OmNsZ2xveDM6LSw9Y2dsaGxramp4Mzo6KjBja29nbGxob294Mzo_Li5jamhraXg1KWMqNj8yMjstdSwxPDssKjFlMDEsOzhlb2UcDGVlZW5lbmVuZW5lZW9taW9mbWlpZmdtbWhlZW5lbmVuZW5lb29nb2hpbG1mZW5wbmVucG5lb2Vlbg--" /> 
     </links> 
     <thumbnail url="http://thumbs.buscape.com.br/T100x100/__2.157-71a5906.jpg" /> 
     <price> 
      <currency abbreviation="BRL" /> 
      <value>27.06</value> 
      <parcel> 
       <value>13.95</value> 
       <number>2</number> 
       <interest>2.06</interest> 
      </parcel> 
     </price> 
     <seller oneClickBuyValue="0" oneClickBuy="false" advertiserId="0" pagamentoDigital="false" isTrustedStore="true" id="157"> 
      <sellerName>Siciliano</sellerName> 
      <thumbnail url="http://imagem.buscape.com.br/vitrine/logo157.gif" /> 
      <links> 
       <link type="seller" url="http://www.siciliano.com.br/default.asp?parc=BULL&amp;utm_source=buscape&amp;utm_medium=buscape&amp;utm_campaign=buscape" /> 
      </links> 
      <contacts> 
       <contact label="SAC" value="11-39334020" /> 
       <contact label="Televendas" value="03007893649" /> 
       <contact label="Televendas" value="11-36494747" /> 
      </contacts> 
      <rating> 
       <userAverageRating> 
        <numComments>12177</numComments> 
        <rating>7.0</rating> 
       </userAverageRating> 
       <eBitRating> 
        <numComments>12177</numComments> 
        <rating>sob-avaliação</rating> 
        <ratingNew>e-bit Loja Nova</ratingNew> 
        <ratingId>5</ratingId> 
       </eBitRating> 
      </rating> 
     </seller> 
    </offer> 
</Result> 

---

---

나는 내부 썸네일에서 URL과 링크의 URL을 (느릅 나무는 제안 유형이)가 필요합니다. 어떻게이 데이터를 C#으로 가져올 수 있습니까? xml 코드 (동적 인 경우) 문자열이 있습니다.

Answer 1

이 XML 역 직렬화/[여기]

/// <summary> 
/// Serializes an object. 
/// </summary> 
/// <typeparam name="T"></typeparam> 
/// <param name="serializableObject"></param> 
/// <param name="fileName"></param> 
public void SerializeObject<T>(T serializableObject, string fileName) 
{ 
    if (serializableObject == null) { return; } 

    try 
    { 
     XmlDocument xmlDocument = new XmlDocument(); 
     XmlSerializer serializer = new XmlSerializer(serializableObject.GetType()); 
     using (MemoryStream stream = new MemoryStream()) 
     { 
      serializer.Serialize(stream, serializableObject); 
      stream.Position = 0; 
      xmlDocument.Load(stream); 
      xmlDocument.Save(fileName); 
      stream.Close(); 
     } 
    } 
    catch (Exception ex) 
    { 
     //Log exception here 
    } 
} 


/// <summary> 
/// Deserializes an xml file into an object list 
/// </summary> 
/// <typeparam name="T"></typeparam> 
/// <param name="fileName"></param> 
/// <returns></returns> 
public T DeSerializeObject<T>(string fileName) 
{ 
    if (string.IsNullOrEmpty(fileName)) { return default(T); } 

    T objectOut = default(T); 

    try 
    { 
     string attributeXml = string.Empty; 

     XmlDocument xmlDocument = new XmlDocument(); 
     xmlDocument.Load(fileName); 
     string xmlString = xmlDocument.OuterXml; 

     using (StringReader read = new StringReader(xmlString)) 
     { 
      Type outType = typeof(T); 

      XmlSerializer serializer = new XmlSerializer(outType); 
      using (XmlReader reader = new XmlTextReader(read)) 
      { 
       objectOut = (T)serializer.Deserialize(reader); 
       reader.Close(); 
      } 

      read.Close(); 
     } 
    } 
    catch (Exception ex) 
    { 
     //Log exception here 
    } 

    return objectOut; 
}