mysqli_stmt_fetch()가 작동하지 않습니다.

Question

mysqli_stmt_fetch() 문에서 값을 저장하려고합니다. 내 응용 프로그램을 실행하면이 변수에 No Value가 반환됩니다. 나는 PHP를 처음 사용하기 때문에이 파일을 완전히 디버그 할 수 없다. 어디에서 버그가 있습니까?

내 PHP 파일 : 나는 registerUser의 함수 내에서 위치 설정하려고

<?php 
    require("password.php"); 

    $connect = mysqli_connect("website", "account", "my_pass", "db"); 

    $name = $_POST["name"]; 
    $theme = $_POST["theme"]; 
    $username = $_POST["username"]; 
    $email = $_POST["email"]; 
    $defaultRadius = $_POST["radius"]; 
    $password = $_POST["password"]; 

    function registerUser() { 
     global $connect, $name, $username, $theme, $email, $defaultRadius, $password; 
     $passwordHash = password_hash($password, PASSWORD_DEFAULT); 
     $statement = mysqli_prepare($connect, "INSERT INTO user (name, username, theme, email, default_radius, password) VALUES (?, ?, ?, ?, ?, ?)"); 
     mysqli_stmt_bind_param($statement, "ssssss", $name, $username, $theme, $email, $defaultRadius, $passwordHash); 
     mysqli_stmt_execute($statement); 
     mysqli_stmt_bind_result($statement, $colUserID, $colName, $colUsername, $colTheme, $colEmail, $colDefaultRadius, $colPassword); 
     while(mysqli_stmt_fetch($statement)){ 
      $response["userId"] = $colUserID; 
     } 
     mysqli_stmt_close($statement); 
    } 

    function usernameAvailable() { 
     global $connect, $username; 
     $statement = mysqli_prepare($connect, "SELECT * FROM user WHERE username = ?"); 
     mysqli_stmt_bind_param($statement, "s", $username); 
     mysqli_stmt_execute($statement); 
     mysqli_stmt_store_result($statement); 
     $count = mysqli_stmt_num_rows($statement); 
     mysqli_stmt_close($statement); 
     if ($count < 1){ 
      return true; 
     } else { 
      return false; 
     } 
    } 

    $response = array(); 
    $response["success"] = false; 
    $response["reason"] = 0; 

    if (usernameAvailable()){ 
     registerUser(); 
     $response["success"] = true; 
    } else { 
     $response["reason"] = 1; 
    } 

    echo json_encode($response); 
?> 

변수. 상태 :

while(mysqli_stmt_fetch($statement)){ 
    $response["userId"] = $colUserID; 
} 

어떤 도움을 주셔서 감사합니다!

는

편집 :은 다음과 내 새/현재 코드가 될 때 :

<?php 
    require("password.php"); 

    $connect = mysqli_connect("xenicdev.x10host.com", "xenicdev_root", "shadow1", "xenicdev_data"); 

    $name = $_POST["name"]; 
    $theme = $_POST["theme"]; 
    $username = $_POST["username"]; 
    $email = $_POST["email"]; 
    $defaultRadius = $_POST["radius"]; 
    $password = $_POST["password"]; 

    function registerUser() { 
     global $connect, $name, $username, $theme, $email, $defaultRadius, $password, $response; 
     $passwordHash = password_hash($password, PASSWORD_DEFAULT); 
     $statement = mysqli_prepare($connect, "INSERT INTO user (name, username, theme, email, default_radius, password) VALUES (?, ?, ?, ?, ?, ?)"); 
     mysqli_stmt_bind_param($statement, "ssssss", $name, $username, $theme, $email, $defaultRadius, $passwordHash); 
     mysqli_stmt_execute($statement); 
     mysqli_stmt_bind_result($statement, $colUserID, $colName, $colUsername, $colTheme, $colEmail, $colDefaultRadius, $colPassword); 
     while(mysqli_stmt_fetch($statement)){ 
      return $colUserID; 
     } 
    } 

    function usernameAvailable() { 
     global $connect, $username; 
     $statement = mysqli_prepare($connect, "SELECT * FROM user WHERE username = ?"); 
     mysqli_stmt_bind_param($statement, "s", $username); 
     mysqli_stmt_execute($statement); 
     mysqli_stmt_store_result($statement); 
     $count = mysqli_stmt_num_rows($statement); 
     mysqli_stmt_close($statement); 
     if ($count < 1){ 
      return true; 
     } else { 
      return false; 
     } 
    } 

    $response = array(); 
    $response["success"] = false; 
    $response["reason"] = 0; 

    if (usernameAvailable()){ 
     $userId = registerUser(); 
     $response["userId"] = $userId; 
     $response["success"] = true; 
    } else { 
     $response["reason"] = 1; 
    } 

    echo json_encode($response); 
?> 

그것은 ID는 SQL에서 null가 아닌 유의하시기 바랍니다 ...하지만 대신 ID의 "userId를"null를 돌려줍니다 데이터 베이스. 당신이 last insertuserID 필요한 경우

public class RegisterRequest extends StringRequest { 

    private static final String REGISTER_REQUEST_URL = "http://xenicdev.x10host.com/Register.php"; 
    private Map<String, String> params; 

    public RegisterRequest(String name, String username, int themeId, String password, String email, int defaultRadius, Response.Listener<String> listener) { 
     super(Method.POST, REGISTER_REQUEST_URL, listener, null); 
     params = new HashMap<>(); 
     params.put("name", name); 
     params.put("username", username); 
     params.put("theme", themeId + ""); 
     params.put("email", email); 
     params.put("radius", defaultRadius + ""); 
     params.put("password", password); 
    } 

    @Override 
    public Map<String, String> getParams() { 
     return params; 
    } 
} 

Answer 1

안녕하세요 당신이 시도 할 수 있습니다 : 내 테스트의 경우, ID는 안드로이드에서이 PHP 파일을 호출하는 데 사용 8.

StringRequest 코드입니다. 그럼 당신의 일부를 변경 도움이됩니다 code

<?php 
require("password.php"); 
    $connect = mysqli_connect("xenicdev.x10host.com", "xenicdev_root", "shadow1", "xenicdev_data"); 
    $name = $_POST["name"]; 
    $theme = $_POST["theme"]; 
    $username = $_POST["username"]; 
    $email = $_POST["email"]; 
    $defaultRadius = $_POST["radius"]; 
    $password = $_POST["password"]; 

    function registerUser() { 
     global $connect, $name, $username, $theme, $email, $defaultRadius, $password; 

     $passwordHash = password_hash($password, PASSWORD_DEFAULT); 
$stmt = $connect->prepare("INSERT INTO user (name, username, theme, email, default_radius, password) VALUES (?, ?, ?, ?, ?, ?)"); 
$stmt->bind_param("ssssss", $name, $username, $theme, $email, $defaultRadius, $passwordHash); 
$stmt->execute(); 
return $userID = $stmt->insert_id; 
    } 

    function usernameAvailable() { 
     global $connect, $username; 
     $statement = mysqli_prepare($connect, "SELECT * FROM user WHERE username = ?"); 
     mysqli_stmt_bind_param($statement, "s", $username); 
     mysqli_stmt_execute($statement); 
     mysqli_stmt_store_result($statement); 
     $count = mysqli_stmt_num_rows($statement); 
     mysqli_stmt_close($statement); 
     if ($count < 1){ 
      return true; 
     } else { 
      return false; 
     } 
    } 

    $response = array(); 
    $response["success"] = false; 
    $response["reason"] = 0; 


    if (usernameAvailable()){ 
     $userID = registerUser(); 
     $response["success"] = true; 
     $response["userId"] = $userID; 
    } else { 
     $response["reason"] = 1; 
    } 

    echo json_encode($response); 
?>