ValidationException : TraversableResolver.isReachable() 호출이 예외를 던졌습니다

Question

데이터베이스와 연결되는 간단한 가입 양식을 만들려고 할 때이 오류가 발생했습니다. 우분투를 사용합니다.

--- (RELOAD) --- 

[info] play - database [default] connected at jdbc:mysql://localhost/login 
[info] play - Application started (Dev) 
[error] application - 

! @6f07fm4f0 - Internal server error, for request [POST /signup] -> 

play.core.ActionInvoker$$anonfun$receive$1$$anon$1: Execution exception [[ValidationException: Call to TraversableResolver.isReachable() threw an exception]] 
    at play.core.ActionInvoker$$anonfun$receive$1.apply(Invoker.scala:134) [play_2.9.1.jar:2.0.4] 
    at play.core.ActionInvoker$$anonfun$receive$1.apply(Invoker.scala:115) [play_2.9.1.jar:2.0.4] 
    at akka.actor.Actor$class.apply(Actor.scala:318) [akka-actor.jar:2.0.2] 
    at play.core.ActionInvoker.apply(Invoker.scala:113) [play_2.9.1.jar:2.0.4] 
    at akka.actor.ActorCell.invoke(ActorCell.scala:626) [akka-actor.jar:2.0.2] 
    at akka.dispatch.Mailbox.processMailbox(Mailbox.scala:197) [akka-actor.jar:2.0.2] 
Caused by: javax.validation.ValidationException: Call to TraversableResolver.isReachable() threw an exception 
    at org.hibernate.validator.engine.ValidatorImpl.isValidationRequired(ValidatorImpl.java:1251) ~[hibernate-validator.jar:4.2.0.Final] 
    at org.hibernate.validator.engine.ValidatorImpl.validateConstraint(ValidatorImpl.java:448) ~[hibernate-validator.jar:4.2.0.Final] 
    at org.hibernate.validator.engine.ValidatorImpl.validateConstraintsForDefaultGroup(ValidatorImpl.java:397) ~[hibernate-validator.jar:4.2.0.Final] 
    at org.hibernate.validator.engine.ValidatorImpl.validateConstraintsForCurrentGroup(ValidatorImpl.java:361) ~[hibernate-validator.jar:4.2.0.Final] 
    at org.hibernate.validator.engine.ValidatorImpl.validateInContext(ValidatorImpl.java:313) ~[hibernate-validator.jar:4.2.0.Final] 
    at org.hibernate.validator.engine.ValidatorImpl.validate(ValidatorImpl.java:139) ~[hibernate-validator.jar:4.2.0.Final] 
Caused by: java.lang.RuntimeException: No @javax.persistence.Id field found in class [class models.User] 
    at play.db.ebean.Model._idAccessors(Model.java:39) ~[play_2.9.1.jar:2.0.4] 
    at play.db.ebean.Model._getId(Model.java:52) ~[play_2.9.1.jar:2.0.4] 
    at play.db.ebean.Model.hashCode(Model.java:183) ~[play_2.9.1.jar:2.0.4] 
    at org.hibernate.validator.engine.resolver.SingleThreadCachedTraversableResolver$TraversableHolder.buildHashCode(SingleThreadCachedTraversableResolver.java:153) ~[hibernate-validator.jar:4.2.0.Final] 
    at org.hibernate.validator.engine.resolver.SingleThreadCachedTraversableResolver$TraversableHolder.<init>(SingleThreadCachedTraversableResolver.java:114) ~[hibernate-validator.jar:4.2.0.Final] 
    at org.hibernate.validator.engine.resolver.SingleThreadCachedTraversableResolver$TraversableHolder.<init>(SingleThreadCachedTraversableResolver.java:96) ~[hibernate-validator.jar:4.2.0.Final] 

: 터미널에서

@(user : Form[User]) 

@import helper._ 

@helper.form(action=routes.Signup.submit){ 
    @inputText(
     user("username"), 
     '_label -> "Username", 
     '_help -> "Put your username here" 
    ) 

    @inputPassword(
     user("password"), 
     '_label -> "Password", 
     '_help -> "Put your password here" 
    ) 

    @inputPassword(
     user("repeatpassword"), 
     '_label -> "Repeat password", 
     '_help -> "Put your password again" 
    ) 

    @inputText(
     user("email"), 
     '_label -> "Email", 
     '_help -> "Put your email here" 
    ) 

    <input type="submit" value="Sign up" /> 
} 

formsup.scala.html User.java

package models; 

import java.util.List; 

import javax.persistence.Entity; 
import javax.validation.constraints.NotNull; 

import play.data.validation.Constraints.Email; 
import play.data.validation.Constraints.MinLength; 
import play.data.validation.Constraints.Required; 
import play.db.ebean.Model; 


@Entity 
public class User extends Model{ 
    @Required@NotNull@MinLength(6) 
    public String username; 

    @Required@NotNull@MinLength(6) 
    public String password; 

    @Required@Email 
    public String email; 

// public User(){} 
// 
// public User(String username,String password,String email){ 
//  this.username=username; 
//  this.password=password; 
//  this.email=email; 
// } 

    public static Finder<Long, User> find = new Finder(Long.class, User.class); 

    public static List<User> all(){ 
     return find.all(); 
    } 
    public static void create(User user){ 
     user.save(); 
    } 

} 

Signup.java

package controllers; 

import models.User; 
import play.data.Form; 
import play.mvc.*; 
import views.html.signup.*; 
import views.html.*; 

public class Signup extends Controller{ 
    public static Form<User> form = form(User.class); 

    public static Result blank(){ 
     return ok(formsu.render(form)); 
    } 
    public static Result submit(){ 
     Form<User> fillForm = form.bindFromRequest(); // Play mark this line !!! 
     if(fillForm.hasErrors()) { 
      return badRequest(formsu.render(fillForm)); 
     } 
     else{ 
      User created = fillForm.get(); 
      return ok(result.render(created)); 
     } 
    } 
} 

: 다음은 내 코드입니다

"index"와 "main"html은 괜찮습니다. (해결해주세요. 검색을 시도하지만이 오류를 해결할 수 없습니다. 도와 주셔서 감사합니다!!!

Answer 1

예외 상태에서 모델에는 @Id으로 주석이 달린 id 필드가 필요합니다. Play의 유효성 검사 라이브러리! 모델 필드에 액세스 할 수 없으므로 id, username, password 및 email 필드에 getter 및 setter를 추가하기 만하면됩니다.