다른보기 기능으로 리디렉션

Question

사용자가 로그인 할 때 URL에 '/ login /'을 사용하는 대신 단순히 색인으로 리디렉션하고 싶습니다.

로그인과 색인을위한 두 개의보기 기능이 있습니다.

인덱스보기

def index(request): 

    context = { 

    } 
    return render(request, 'index.html', context) 

로그인보기

def login(request): 

    username = request.POST.get('username', '') 
    password = request.POST.get('password', '') 

    user = auth.authenticate(username=username, password=password) 

    if user is not None: 
     auth.login(request, user) 
    else: 
     print('Wrong user') 

    return redirect('index') #<------ Something like that(?) 

URL 패턴

urlpatterns = [ 
      url(r'^$', views.index, name='index'), 

      url(r'^login/$', views.login, name='login'),  
] 

콘솔 오류 :

Correct user 
Internal Server Error: /Crowd/login/ 
Traceback (most recent call last): 
    File "C:\Anaconda3\Lib\site-packages\django\core\handlers\base.py", line 149, in get_response 
    response = self.process_exception_by_middleware(e, request) 
    File "C:\Anaconda3\Lib\site-packages\django\core\handlers\base.py", line 147, in get_response 
    response = wrapped_callback(request, *callback_args, **callback_kwargs) 
    File "C:\Users\Rasmus\workspace\Crowd\src\Cr\views.py", line 66, in login 
    return redirect('index') 
    File "C:\Anaconda3\Lib\site-packages\django\shortcuts.py", line 116, in redirect 
    return redirect_class(resolve_url(to, *args, **kwargs)) 
    File "C:\Anaconda3\Lib\site-packages\django\shortcuts.py", line 204, in resolve_url 
    return urlresolvers.reverse(to, args=args, kwargs=kwargs) 
    File "C:\Anaconda3\Lib\site-packages\django\core\urlresolvers.py", line 600, in reverse 
    return force_text(iri_to_uri(resolver._reverse_with_prefix(view, prefix, *args, **kwargs))) 
    File "C:\Anaconda3\Lib\site-packages\django\core\urlresolvers.py", line 508, in _reverse_with_prefix 
    (lookup_view_s, args, kwargs, len(patterns), patterns)) 
django.core.urlresolvers.NoReverseMatch: Reverse for 'index' with arguments '()' and keyword arguments '{}' not found. 0 pattern(s) tried: [] 
[14/Sep/2016 19:46:12] "POST /Crowd/login/ HTTP/1.1" 500 88875 

Answer 1

# views.py 
def login(...): 
    # ... 
    return redirect('home') 

과 : 귀하의 답변에 대한

# urls.py 
urlpatterns = [ 
    url(r'^$', 'views.index', name='home'), 
    # ... 
]