형식 Authlogic는 Authlogic, @의 시간 형식을 사용하여 문자열

Question

을"last_login_at "

Mon Apr 12 16:52:56 -0400 2010 

어떻게 난도질 수보다 사용자 친화적 인 문자열로

Answer 1

사용,

@user.last_login_at.d.strftime(‘%b %d, %Y’) 

# will print April 12, 2010 

The following are the format codes; 
Format Meaning 
%a The abbreviated weekday name (“Sun’’) 
%A The full weekday name (“Sunday’’) 
%b The abbreviated month name (“Jan’’) 
%B The full month name (“January’’) 
%c The preferred local date and time representation 
%d Day of the month (01..31) 
%H Hour of the day, 24-hour clock (00..23) 
%I Hour of the day, 12-hour clock (01..12) 
%j Day of the year (001..366) 
%m Month of the year (01..12) 
%M Minute of the hour (00..59) 
%p Meridian indicator (“AM’’ or “PM’’) 
%S Second of the minute (00..60) 
%U Week number of the current year, starting with the first Sunday as the first day of the first week (00..53) 
%W Week number of the current year, starting with the first Monday as the first day of the first week (00..53) 
%w Day of the week (Sunday is 0, 0..6) 
%x Preferred representation for the date alone, no time 
%X Preferred representation for the time alone, no date 
%y Year without a century (00..99) 
%Y Year with century 
%Z Time zone name 
%% Literal “%’’ character 

Answer 2

사용 strftime? :

@user.last_login_at.strftime("%d %m %Y %I:%M:%S") 

Answer 3

다른 사람들이 지적했듯이 strftime이 작동하지만 레일스 애플리케이션에서 authlogic을 사용하는 경우 미리 실행 된 시간 도우미가 있습니다. 예 : @user.last_login_at.to_s(:long).