스탠포드 파서를 사용하여 엔티티를 추출하는 방법은 무엇입니까?

Question

OpenNLP를 사용하고 있지만 정확한 이름, 위치, 조직 엔티티를 제공하지 않습니다. 스탠포드 파서를 사용하여 엔티티를 추출하는 방법은 무엇입니까?

Answer 1

내 코드가 도움이됩니다. 여기

내 코드입니다

public class stanfrdIntro { 

    public static void main(String[] args) throws IOException, SAXException, 
    TikaException { 

     String serializedClassifier = "classifiers/english.all.3class.distsim.crf.ser.gz"; 


     AbstractSequenceClassifier<CoreLabel> classifier = CRFClassifier 
       .getClassifierNoExceptions(serializedClassifier); 

     if (args.length > 1) { 
     String fileContents = IOUtils.slurpFile(args[1]); 
     List<List<CoreLabel>> out = classifier.classify(fileContents); 
     for (List<CoreLabel> sentence : out) { 
     for (CoreLabel word : sentence) { 
     System.out.print(word.word() + '/' + 
     word.get(CoreAnnotations.AnswerAnnotation.class) + ' '); 
     } 
     System.out.println(); 
     } 
out = classifier.classifyFile(args[1]); 
     for (List<CoreLabel> sentence : out) { 
     for (CoreLabel word : sentence) { 
     System.out.print(word.word() + '/' + 
     word.get(CoreAnnotations.AnswerAnnotation.class) + ' '); 
     } 
     System.out.println(); 
     } 

     } else { 
     String s1 = "Good afternoon Rahul Kulhari, how are you today?"; 
     String s2 = 
     "I go to school at Stanford University, which is located in California."; 
     stanfrdIntro si = new stanfrdIntro(); 
     String s1 = si.contentEx(); 
     s1 = s1.replaceAll("\\s+", " "); 
     System.out.println(s1); 
     String t=classifier.classifyWithInlineXML(s1); 
     System.out.println(Arrays.toString(getTagValues(t).toArray())); 

     XPath xpath = XPathFactory.newInstance().newXPath(); 
     XPathExpression expr = xpath.compile("//PERSON/text()"); 
     Object value = expr.evaluate(doc, XPathConstants.STRING); 
     System.out.println(t); 
     System.out.println(classifier.classifyToString(s1)); 
     Set<String> s=classifier.; 
     for(String s13: s) 
     { 
      System.out.println(s13); 
     } 
     System.out.println(classifier.classifyWithInlineXML(s1)); 
     System.out.println(classifier.classifyToString(s1, "xml", true)); 
     int i=0; 
     for (List<CoreLabel> lcl : classifier.classify(s2)) { 
     for (CoreLabel cl : lcl) { 
     System.out.println(i++ + ":"); 
     System.out.println(cl); 
} 
} 
} 
    } 


}