이 스레드는 지금 죽었을 수도 있지만 데이터베이스의 양식으로 작업하고 사용자가 고유 한 식별 번호가있는 양식에 표시된 특정 레코드에 파일을 첨부해야하는 경우이 작업은 가능하지만 .NET으로 작성된 외부 응용 프로그램에서해야합니다. 필요한 코드를 제공하여 시작할 수 있도록해야합니다. vb.net은 VBA와 매우 유사합니다.
당신이해야 할 일은 Windows 양식 프로젝트를 만들고 Microsoft Access Core dll에 대한 참조를 추가하고 너겟에서 Google 드라이브 API에 대한 너겟 패키지를 다운로드하는 것입니다.
Imports Google
Imports Google.Apis.Services
Imports Google.Apis.Drive.v2
Imports Google.Apis.Auth.OAuth2
Imports Google.Apis.Drive.v2.Data
Imports System.Threading
Public Class GoogleDriveAuth
Public Shared Function GetAuthentication() As DriveService
Dim ClientIDString As String = "Your Client ID"
Dim ClientSecretString As String = "Your Client Secret"
Dim ApplicationNameString As String = "Your Application Name"
Dim secrets = New ClientSecrets()
secrets.ClientId = ClientIDString
secrets.ClientSecret = ClientSecretString
Dim scope = New List(Of String)
scope.Add(DriveService.Scope.Drive)
Dim credential = GoogleWebAuthorizationBroker.AuthorizeAsync(secrets, scope, "user", CancellationToken.None).Result()
Dim initializer = New BaseClientService.Initializer
initializer.HttpClientInitializer = credential
initializer.ApplicationName = ApplicationNameString
Dim Service = New DriveService(initializer)
Return Service
End Function
End Class
다음 다음
서비스처럼 폼로드 이벤트에이 함수를 호출 하위 또는 함수에서 사용할 수있는 귀하의 수입에 따라 DriveService과 같은 공용 공유 서비스를 만들 드라이브 서비스 권한을 부여합니다이 코드 = GoogleDriveAuth.GetAuthentication
Microsoft Access 12에 대한 프로젝트 참조를 추가하십시오.0 개체 라이브러리 또는 당신은
이 그런 형태로 모양이 코드 조각이 더에서 레코드의 값을 얻을 및 폴더의 선택
Private Sub UploadAttachments()
Dim NumberExtracted As String
Dim oAccess As Microsoft.Office.Interop.Access.Application = Nothing
Dim connectedToAccess As Boolean = False
Dim SelectedFolderIdent As String = "Your Upload Folder ID"
Dim CreatedFolderIdent As String
Dim tryToConnect As Boolean = True
Dim oForm As Microsoft.Office.Interop.Access.Form
Dim oCtls As Microsoft.Office.Interop.Access.Controls
Dim oCtl As Microsoft.Office.Interop.Access.Control
Dim sForm As String 'name of form to show
sForm = "Your Form Name"
Try
While tryToConnect
Try
' See if can connect to a running Access instance
oAccess = CType(Marshal.GetActiveObject("Access.Application"), Microsoft.Office.Interop.Access.Application)
connectedToAccess = True
Catch ex As Exception
Try
' If couldn't connect to running instance of Access try to start a running Access instance And get an updated version of the database
oAccess = CType(CreateObject("Access.Application"), Microsoft.Office.Interop.Access.Application)
oAccess.Visible = True
oAccess.OpenCurrentDatabase("Your Database Path", False)
connectedToAccess = True
Catch ex2 As Exception
Dim res As DialogResult = MessageBox.Show("COULD NOT CONNECT TO OR START THE DATABASE" & vbNewLine & ex2.Message, "Warning", MessageBoxButtons.AbortRetryIgnore, MessageBoxIcon.Warning)
If res = System.Windows.Forms.DialogResult.Abort Then
Exit Sub
End If
If res = System.Windows.Forms.DialogResult.Ignore Then
tryToConnect = False
End If
End Try
End Try
' We have connected successfully; stop trying
tryToConnect = False
End While
' Start a new instance of Access for Automation:
' Make sure Access is visible:
If Not oAccess.Visible Then oAccess.Visible = True
' For Each oForm In oAccess.Forms
' oAccess.DoCmd.Close(ObjectType:=Microsoft.Office.Interop.Access.AcObjectType.acForm, ObjectName:=oForm.Name, Save:=Microsoft.Office.Interop.Access.AcCloseSave.acSaveNo)
' Next
' If Not oForm Is Nothing Then
' System.Runtime.InteropServices.Marshal.ReleaseComObject(oForm)
' End If
' oForm = Nothing
' Select the form name in the database window and give focus
' to the database window:
' oAccess.DoCmd.SelectObject(ObjectType:=Microsoft.Office.Interop.Access.AcObjectType.acForm, ObjectName:=sForm, InDatabaseWindow:=True)
' Show the form:
' oAccess.DoCmd.OpenForm(FormName:=sForm, View:=Microsoft.Office.Interop.Access.AcFormView.acNormal)
' Use Controls collection to edit the form:
oForm = oAccess.Forms(sForm)
oCtls = oForm.Controls
oCtl = oCtls.Item("The Name Of The Control Where The Id Number Is On The Form")
oCtl.Enabled = True
' oCtl.SetFocus()
NumberExtracted = oCtl.Value
System.Runtime.InteropServices.Marshal.ReleaseComObject(oCtl)
oCtl = Nothing
' Hide the Database Window:
' oAccess.DoCmd.SelectObject(ObjectType:=Microsoft.Office.Interop.Access.AcObjectType.acForm, ObjectName:=sForm, InDatabaseWindow:=True)
' oAccess.RunCommand(Command:=Microsoft.Office.Interop.Access.AcCommand.acCmdWindowHide)
' Set focus back to the form:
' oForm.SetFocus()
' Release Controls and Form objects:
System.Runtime.InteropServices.Marshal.ReleaseComObject(oCtls)
oCtls = Nothing
System.Runtime.InteropServices.Marshal.ReleaseComObject(oForm)
oForm = Nothing
' Release Application object and allow Access to be closed by user:
If Not oAccess.UserControl Then oAccess.UserControl = True
System.Runtime.InteropServices.Marshal.ReleaseComObject(oAccess)
oAccess = Nothing
If NumberExtracted = Nothing Then
MsgBox("The Number Could Not Be Obtained From The Form" & vbNewLine & vbNewLine & "Please Ensure You Have The Form Open Before Trying To Upload")
Exit Sub
End If
If CheckForDuplicateFolder(SelectedFolderIdent, NumberExtracted + " - ATC") = True Then
CreatedFolderIdent = GetCreatedFolderID(NumberExtracted + " - ATC", SelectedFolderIdent)
DriveFilePickerUploader(CreatedFolderIdent)
Else
CreateNewDriveFolder(NumberExtracted + " - ATC", SelectedFolderIdent)
CreatedFolderIdent = GetCreatedFolderID(NumberExtracted + " - ATC", SelectedFolderIdent)
DriveFilePickerUploader(CreatedFolderIdent)
End If
Catch EX As Exception
MsgBox("The Number Could Not Be Obtained From The Form" & vbNewLine & vbNewLine & "Please Ensure You Have The Form Open Before Trying To Upload" & vbNewLine & vbNewLine & EX.Message)
Exit Sub
Finally
If Not oCtls Is Nothing Then
System.Runtime.InteropServices.Marshal.ReleaseComObject(oCtls)
oCtls = Nothing
End If
If Not oForm Is Nothing Then
System.Runtime.InteropServices.Marshal.ReleaseComObject(oForm)
oForm = Nothing
End If
If Not oAccess Is Nothing Then
System.Runtime.InteropServices.Marshal.ReleaseComObject(oAccess)
oAccess = Nothing
End If
End Try
End
End Sub
확인에 파일을 업로드 할 뭐든지 버전 목적지 업로드 폴더
Public Function CheckForDuplicateFolder(ByVal FolderID As String, ByVal NewFolderNameToCheck As String) As Boolean
Dim ResultToReturn As Boolean = False
Try
Dim request = Service.Files.List()
Dim requeststring As String = ("'" & FolderID & "' in parents And mimeType='application/vnd.google-apps.folder' And trashed=false")
request.Q = requeststring
Dim FileList = request.Execute()
For Each File In FileList.Items
If File.Title = NewFolderNameToCheck Then
ResultToReturn = True
End If
Next
Catch EX As Exception
MsgBox("THERE HAS BEEN AN ERROR" & EX.Message)
End Try
Return ResultToReturn
End Function
만들기 새 드라이브 폴더
Public Sub CreateNewDriveFolder(ByVal DirectoryName As String, ByVal ParentFolder As String)
Try
Dim body1 = New Google.Apis.Drive.v2.Data.File
body1.Title = DirectoryName
body1.Description = "Created By Automation"
body1.MimeType = "application/vnd.google-apps.folder"
body1.Parents = New List(Of ParentReference)() From {New ParentReference() With {.Id = ParentFolder}}
Dim file1 As Google.Apis.Drive.v2.Data.File = Service.Files.Insert(body1).Execute()
Catch EX As Exception
MsgBox("THERE HAS BEEN AN ERROR" & EX.Message)
End Try
End Sub
에서 중복 폴더3210
생성 된 폴더 ID를 업로드
새로 만든 폴더
Public Sub DriveFilePickerUploader(ByVal ParentFolderID As String)
Try
ProgressBar1.Value = 0
Dim MimeTypeToUse As String
Dim dr As DialogResult = Me.OpenFileDialog1.ShowDialog()
If (dr = System.Windows.Forms.DialogResult.OK) Then
Dim file As String
Else : Exit Sub
End If
Dim i As Integer = 0
For Each file In OpenFileDialog1.FileNames
MimeTypeToUse = GetMimeType(file)
Dim filetitle As String = (OpenFileDialog1.SafeFileNames(i))
Dim body2 = New Google.Apis.Drive.v2.Data.File
body2.Title = filetitle
body2.Description = "J-T Auto File Uploader"
body2.MimeType = MimeTypeToUse
body2.Parents = New List(Of ParentReference)() From {New ParentReference() With {.Id = ParentFolderID}}
Dim byteArray = System.IO.File.ReadAllBytes(file)
Dim stream = New System.IO.MemoryStream(byteArray)
Dim request2 = Service.Files.Insert(body2, stream, MimeTypeToUse)
request2.Upload()
Next
Catch EX As Exception
MsgBox("THERE HAS BEEN AN ERROR" & EX.Message)
End Try
End Sub
파일 존재의 MIME 타입을 얻을 수있는 파일 대화 상자에서 선택한 파일을 업로드 할 수
Public Function GetCreatedFolderID(ByVal FolderName As String, ByVal FolderID As String) As String
Dim ParentFolder As String
Try
Dim request = Service.Files.List()
Dim requeststring As String = ("'" & FolderID & "' in parents And mimeType='application/vnd.google-apps.folder' And title='" & FolderName & "' And trashed=false")
request.Q = requeststring
Dim Parent = request.Execute()
ParentFolder = (Parent.Items(0).Id)
Catch EX As Exception
MsgBox("THERE HAS BEEN AN ERROR" & EX.Message)
End Try
Return ParentFolder
End Function
드라이브 파일 선택기 업 로더를 가져 오기
Public Shared Function GetMimeType(ByVal file As String) As String
Dim mime As String = Nothing
Dim MaxContent As Integer = CInt(New FileInfo(file).Length)
If MaxContent > 4096 Then
MaxContent = 4096
End If
Dim fs As New FileStream(file, FileMode.Open)
Dim buf(MaxContent) As Byte
fs.Read(buf, 0, MaxContent)
fs.Close()
Dim result As Integer = FindMimeFromData(IntPtr.Zero, file, buf, MaxContent, Nothing, 0, mime, 0)
Return mime
End Function
<DllImport("urlmon.dll", CharSet:=CharSet.Auto)> _
Private Shared Function FindMimeFromData(_
ByVal pBC As IntPtr, _
<MarshalAs(UnmanagedType.LPWStr)> _
ByVal pwzUrl As String, _
<MarshalAs(UnmanagedType.LPArray, ArraySubType:=UnmanagedType.I1, SizeParamIndex:=3)> ByVal _
pBuffer As Byte(), _
ByVal cbSize As Integer, _
<MarshalAs(UnmanagedType.LPWStr)> _
ByVal pwzMimeProposed As String, _
ByVal dwMimeFlags As Integer, _
<MarshalAs(UnmanagedType.LPWStr)> _
ByRef ppwzMimeOut As String, _
ByVal dwReserved As Integer) As Integer
End Function
이 정보가 도움이되기를 바랍니다. 관리자가 이미 완료 했으므로 100 % 확신 할 수 있기를 바랍니다.
나는이 질문에 도움을 줄 수는 없지만 일을 처리하는 매우 복잡한 방법으로 들린다. 사용 가능한 저장 공간이있는 곳으로 FTP 액세스를 할 수있는 가능성이 있습니까? 그런 다음 파일 이름을 저장하고 필요에 따라 파일을 가져와야합니다. – hoopzbarkley
그 유일한 문제는 또 다른 비용입니다. Google은 이미 Google 제품에 대해 비용을 지불하고 있습니다. 회사는 작년에 Gmail을 사용했고 브라우저를 통해 사이트를 만들고 Google 드라이브에 액세스 할 수있었습니다. 속도가 느려지는 컴퓨터에서 발생하는 문제로 인해 Google의 모든 파일은 GD가 아닌 네트워크에 있으므로 동기화 된 폴더를 사용하지 않습니다. 저장소 덤프에 불과한 온라인 어딘가 다른 서버가 서로 다른 사무실에 있기 때문에 이상적입니다. VBA에서 HTML을 사용하여 지금 당장 진행되는 방식을 업로드하기위한 각 단계를 수행해야 할 수도 있습니다. – Glib