2010-12-13 2 views
-2

가능한 중복을 :구두점을 지우는이 정규식도 공백을 잘못 제거합니다. 도움말 :(

var myTxt = "Welcome, Visitor: The Royal Kingdom Of Báenou"; 
myTxt = myTxt.replace(/[^a-zA-Z0-9 ]+/g, '').replace('/ {2,}/',' '); 
alert(myTxt); 

그래서 텍스트 위이 될해야합니다
This regex to strip punctuation also incorrectly makes the word Báenou into Benou

나는 문장 부호 문자을 제거하기 위해 원래 을 다음 정규식을 썼다 :

Welcome Visitor The Royal Kingdom Of Báenou 

그러나 대신 잘못이 생산 Báenou의 á을 삭제 :

: 그래서 내 친구의 도움으로, 나는 아래의 하나에 정규식을 수정
Welcome Visitor The Royal Kingdom Of Benou 

var myTxt = "Welcome, Visitor: The Royal Kingdom Of Báenou"; 
myTxt = 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'').replace('/ {2,}/',' '); 
alert(myTxt); 

그러나 구두점을 제거 할뿐만 아니라 공백도 제거합니다 :

WelcomeVisitorTheRoyalKingdomOfBáenou 

이 작업을보다 효율적으로 수행하기 위해 Xregexp을 다운로드했지만이 정규 표현식을 Xregexp에 쓰는 방법을 잘 모르겠습니다.

어떤 도움이 될만한 방법이 있습니다.

+3

질문을 여러 번 게시하지 마십시오. – EboMike

답변

1

첫 번째 정규식은 문자 클래스 내에 공백 문자가 있고 두 번째 정규식은 포함하지 않습니다. 닫는 ']'앞에 공백을 넣으십시오.

1

글쎄, 내가 볼 수있는 한, 새로운 문자 클래스는 실제로 (명시 적으로 그것을 제외하지 않음으로써) 공간을 포함하고 그것을 삭제합니다.

1

이것은 약간 순진 할 수 있지만 보관하고 싶은 문자를 지정하는 대신 삭제하려는 문자와 일치하지 않는 이유는 무엇입니까?

+0

같은 문제입니다. 유니 코드의 절반이나 다른 유니 코드 중 하나를 선택해야한다면 절대 그렇지 않을 것입니다. 그러나 적절한 정규 표현식 구현을 통해 유니 코드 블록이나 문자 특성을 지정할 수 있어야합니다. – Joey

+0

+1. 문제는 특정 문자를 놓는 것입니다. 따라서 OP가 지켜야 할 것이 무엇이 아니라 떨어 뜨려야하는지 파악하는 것이 자연스러운 일입니다. –

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