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심각한 문제가 있습니다 ... 저는 Spring11, Hibernate3 및 AngularJS와 함께 weblogic 11g에서 응용 프로그램을 만들려고합니다. 2 일 동안, 나는 내 앱을 작동시키는 데 어려움이 있었다. 마침내, 나는이 일을 할 수있었습니다! 내가 나 자신을 인증하고, 내가 각 페이지에서 응용 프로그램에 이동 봄 보안 ... 로그인 페이지에서 저를 리디렉션 왜 난 정말 모를 때 문제가스프링 보안, 항상 로그인 페이지로 리디렉션
하지만, ...
의 Web.xml :
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:jsp="http://java.sun.com/xml/ns/javaee/jsp" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/spring.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>com.bla.Init</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring/spring.xml
</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>encodingFilter</filter-name>
<filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>UTF-8</param-value>
</init-param>
<init-param>
<param-name>forceEncoding</param-name>
<param-value>true</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>encodingFilter</filter-name>
<servlet-name>dispatcher</servlet-name>
</filter-mapping>
<jsp-config>
<jsp-property-group>
<url-pattern>*.jsp</url-pattern>
<page-encoding>UTF-8</page-encoding>
<trim-directive-whitespaces>true</trim-directive-whitespaces>
</jsp-property-group>
</jsp-config>
</web-app>
Spring.xml
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/task/spring-context-3.0.xsd">
<!-- Basic Configurations -->
<context:annotation-config/>
<context:component-scan base-package="test.model"/>
<context:component-scan base-package="test.repository"/>
<context:component-scan base-package="test.service"/>
<context:component-scan base-package="test.controller"/>
<!-- SpringMVC -->
<import resource="spring-mvc.xml"/>
<!-- SpringData -->
<import resource="spring-jpa.xml"/>
<!-- SpringSecurity -->
<import resource="spring-security.xml"/>
</beans>
스프링 security.xml :
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security.xsd">
<security:global-method-security secured-annotations="enabled" />
<security:http auto-config="true" use-expressions="true" access-denied-page="/login?error=403">
<security:intercept-url pattern="/" access="permitAll" />
<security:intercept-url pattern="/protected/**" access="isFullyAuthenticated()" />
<security:form-login login-page="/login" authentication-failure-url="/login?error=403" default-target-url="/protected/home" />
<security:logout invalidate-session="true" logout-success-url="/login" logout-url="/logout" />
</security:http>
<security:authentication-manager>
<security:authentication-provider>
<security:jdbc-user-service
data-source-ref="myRapportDataSource"
users-by-username-query="select nni, password, enabled from system_user where nni = ?"
authorities-by-username-query="select u.nni as login, u.user_role as role from system_user u where u.nni = ?" />
</security:authentication-provider>
</security:authentication-manager>
</beans>
내가 너무 스프링 mvc.xml 추가 : 처음에
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<mvc:annotation-driven/>
<mvc:default-servlet-handler/>
<!-- Login Interceptor -->
<mvc:interceptors>
<mvc:interceptor>
<mvc:mapping path="/protected/**"/>
<bean class="gram.interceptor.LoginInterceptor"/>
</mvc:interceptor>
<!-- workaround to fix IE8 problem -->
<bean id="webContentInterceptor"
class="org.springframework.web.servlet.mvc.WebContentInterceptor">
<property name="cacheSeconds" value="0"/>
<property name="useExpiresHeader" value="true"/>
<property name="useCacheControlHeader" value="true"/>
<property name="useCacheControlNoStore" value="true"/>
</bean>
</mvc:interceptors>
</beans>
를,이 응용 프로그램은 톰캣 6이고 잘 작동,하지만 난 weblogic로 마이 그 레이션해야합니다 10.3.6
아이디어가 있습니까? 나는 거의
매우/
일치 만 URL이
permitAll
액세스 할 수 있습니다
<security:intercept-url pattern="/" access="permitAll" />
으로 내 문제
'pattern = "/ **"access = "permitAll"'을 사용해보십시오. – sp00m
내 하나님 sp00m, 당신은 나를 구 했어요! 나는 단지 그 ... 고마워요! – user3753210