지금 당장 제가 깡충 뛰고있는 노동 조합에 의해 조인되는 2 개의 select 문은 query1과 같은 첫 번째 쿼리와 두 번째 query2를 이름 짓는 것이 었습니다. 내 세 번째 쿼리에서는 where1 또는 query2에 bookno가 없습니다.또 다른 공용체 모두 아직 선택되지 않은 모든 행을 선택합니다.
SELECT distinct t0.BOOKNO, t0.PaxName, t0.Locator, t0.FDATE7,
t0.BOARD, t0.ALIGHT, t0.AIRLINE, t0.FNUMBR, t0.DEP,
t0.ARR, t0.TOUR, t0.ROUTE,
t1.tour, t1.route, t1.sfrom , t1.sto,t1.seq,t0.seq, 'yes'
FROM
( SELECT TOP (100) PERCENT test.dbo.BNAMES.BOOKNO, RTRIM(test.dbo.BNAMES.SRNAME) + '/' + RTRIM(test.dbo.BNAMES.FIRST) + RTRIM(test.dbo.BNAMES.TITLE)
AS PaxName, test.dbo.PNRS.PNR AS Locator, test.dbo.PNRSECTORS.FDATE7, test.dbo.PNRSECTORS.BOARD, test.dbo.PNRSECTORS.ALIGHT,
test.dbo.PNRSECTORS.AIRLINE, test.dbo.PNRSECTORS.FNUMBR, test.dbo.PNRSECTORS.DEP, test.dbo.PNRSECTORS.ARR, test.dbo.BOOKINGS.TOUR,
test.dbo.BOOKINGS.ROUTE, test.dbo.BSTAGES.SEQ,(test.dbo.PNRSECTORS.BOARD + test.dbo.PNRSECTORS.ALIGHT) as both
FROM test.dbo.BOOKINGS LEFT OUTER JOIN
test.dbo.BNAMES ON test.dbo.BOOKINGS.BOOKNO = test.dbo.BNAMES.BOOKNO LEFT OUTER JOIN
test.dbo.BSTAGES ON test.dbo.BNAMES.BOOKNO = test.dbo.BSTAGES.BOOKNO LEFT OUTER JOIN
test.dbo.PNRSECTORS ON test.dbo.BSTAGES.SCODE = test.dbo.PNRSECTORS.SKEY LEFT OUTER JOIN
test.dbo.PNRS ON test.dbo.PNRSECTORS.PNRKEY = test.dbo.PNRS.PNRKEY
WHERE (test.dbo.BSTAGES.STYPE = 3)
ORDER BY test.dbo.BOOKINGS.BOOKNO, test.dbo.BNAMES.SEQ, locator
) t0
INNER JOIN ( SELECT TOUR, ROUTE, OFFSET, SEQ, SCODE, SFROM, STO, (SFROM + STO) AS BOTH
FROM test.dbo.TSTAGES
) t1 ON t1.tour = t0.tour and t1.route = t0.route and (t0.both = t1.both)
union all
SELECT distinct t0.BOOKNO, t0.PaxName, t0.Locator, t0.FDATE7,
t0.BOARD, t0.ALIGHT, t0.AIRLINE, t0.FNUMBR, t0.DEP,
t0.ARR, t0.TOUR, t0.ROUTE,
t1.tour, t1.route, t1.sfrom , t1.sto,t1.seq,t0.seq,'YES'
FROM
( SELECT TOP (100) PERCENT test.dbo.BNAMES.BOOKNO, RTRIM(test.dbo.BNAMES.SRNAME) + '/' + RTRIM(test.dbo.BNAMES.FIRST) + RTRIM(test.dbo.BNAMES.TITLE)
AS PaxName, test.dbo.PNRS.PNR AS Locator, test.dbo.PNRSECTORS.FDATE7, test.dbo.PNRSECTORS.BOARD, test.dbo.PNRSECTORS.ALIGHT,
test.dbo.PNRSECTORS.AIRLINE, test.dbo.PNRSECTORS.FNUMBR, test.dbo.PNRSECTORS.DEP, test.dbo.PNRSECTORS.ARR, test.dbo.BOOKINGS.TOUR,
test.dbo.BOOKINGS.ROUTE, test.dbo.BSTAGES.SEQ,(test.dbo.PNRSECTORS.BOARD + test.dbo.PNRSECTORS.ALIGHT) as both
FROM test.dbo.BOOKINGS LEFT OUTER JOIN
test.dbo.BNAMES ON test.dbo.BOOKINGS.BOOKNO = test.dbo.BNAMES.BOOKNO LEFT OUTER JOIN
test.dbo.BSTAGES ON test.dbo.BNAMES.BOOKNO = test.dbo.BSTAGES.BOOKNO LEFT OUTER JOIN
test.dbo.PNRSECTORS ON test.dbo.BSTAGES.SCODE = test.dbo.PNRSECTORS.SKEY LEFT OUTER JOIN
test.dbo.PNRS ON test.dbo.PNRSECTORS.PNRKEY = test.dbo.PNRS.PNRKEY
WHERE (test.dbo.BSTAGES.STYPE = 1)
ORDER BY test.dbo.BOOKINGS.BOOKNO, test.dbo.BNAMES.SEQ, locator
) t0
INNER JOIN ( SELECT TOUR, ROUTE, OFFSET, SEQ, SCODE, SFROM, STO, (SFROM + STO) AS BOTH
FROM test.dbo.TSTAGES
) t1 ON t1.tour = t0.tour and t1.route = t0.route and t1.seq = t0.seq and (t0.both = t1.both)
order by bookno
END
'주문 BY' 멀리 최적화되어 있습니다. 당신은 두 사람을 내쫓을 수 있습니다. – Quassnoi
감사합니다 그래서 무엇이 해결책이 될 –
@ bugz : 무엇에 대한 해결책? 아직 질문하지 않았습니다. – Quassnoi