JBoss 서블릿 엔진에서 Java/Spring/Maven을 사용하고 MultiActionController를 사용하여 REST API를 설정하고 있습니다. MultiActionController를 사용한 Spring Rest API 정의
예를 들어 어떤I want to do is to group requests to a Single controller
: - :
http://static.springsource.org/spring/docs/3.0.0.M3/spring-framework-reference/html/ch18s02.html 다른 요청에 대한 여러 가지 방법을 가지고 모든
/requestA goes to Controller a
, 같은
/requestA/add.do goes to add-function
/requestA/delete.do goes to delete-function.
내가 봄 설명서를 읽어 봤는데 및 http://static.springsource.org/spring/docs/3.0.0.M3/spring-framework-reference/html/ch16s03.html#mvc-controller-multiaction
하지만 xml의 디스패처 구성에는 몇 가지 문제가 있습니다. Spring MVC에서이를 수행하는 좋은 예를 누구나 알고 있는가? springapp-servlet.xml에
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<bean name="/test/*.do" class="org.test.TestControllerA" />
</beans>
web.xml을
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>springTest</display-name>
<servlet>
<servlet-name>springapp</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springapp</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
</web-app>
및 자바 컨트롤러
public class TestControllerA extends MultiActionController {
@RequestMapping("/TEST")
public ModelAndView add(HttpServletRequest request, HttpServletResponse response) throws Exception {
System.out.println("Test42");
return new ModelAndView();
}
}
봄을 보여주세요 xml – Sudhakar
어떻게 URL 매핑을 수행하고 있습니까? –
코드가 – Hiny