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이 올바른 방법은 스레드 안전 큐을 C++로 처리 할 수 있으며 unsigned char * 배열 바이너리 데이터를 처리 할 수 있습니까?C++에서 스레드 안전 큐
데이터가 주 스레드에서 생성되었으며 생성 된 pthread가 아니라는 점에 유의하십시오. 이는 pthread_mutex_t가 실제로 푸시 및 팝에서 올바르게 작동하는지 질문합니다.
스레드
#include <queue>
#include <pthread.h>
class ts_queue
{
private:
std::queue<unsigned char*> _queue_;
pthread_mutex_t mutex;
pthread_cond_t cond;
public:
ts_queue()
{
pthread_mutex_init(&mutex, NULL);
pthread_cond_init(&cond, NULL);
}
void push(unsigned char* data)
{
pthread_mutex_lock(&mutex);
_queue_.push(data);
pthread_cond_signal(&cond);
pthread_mutex_unlock(&mutex);
}
void pop(unsigned char** popped_data)
{
pthread_mutex_lock(&mutex);
while (_queue_.empty() == true)
{
pthread_cond_wait(&cond, &mutex);
}
*popped_data = _queue_.front();
_queue_.pop();
pthread_mutex_unlock(&mutex);
}
};
소비자 TEST 안전 대기열 :
void *consumer_thread(void *arguments)
{
ts_queue *tsq = static_cast<ts_queue*>(arguments);
while (true)
{
unsigned char* data = NULL;
tsq->pop(&data);
if (data != NULL)
{
// Eureka! Received from the other thread!!!
// Delete it so memory keeps free.
// NOTE: In the real scenario for which I need
// this class, the data received are bitmap pixels
// and at this point it would be processed
delete[] data;
}
}
return 0;
}
생산자 TEST :
void main()
{
ts_queue tsq;
// Create the consumer
pthread_t consumer;
pthread_create(&consumer, NULL, consumer_thread, &tsq));
// Start producing
while(true)
{
// Push data.
// Expected behaviour: memory should never run out, as the
// consumer should receive the data and delete it.
// NOTE: test_data in the real purpose scenario for which I
// need this class would hold bitmap pixels, so it's meant to
// hold binary data and not a string
unsigned char* test_data = new unsigned char [8192];
tsq.push(test_data);
}
return 0;
}