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사용자에게 예 또는 아니오를 입력하도록 요청하는 중입니다. 그렇다면 다시 시작되고 특성이 추가됩니다. 그러나 그것은 내가 Y/N에게 물어 보지 못하게하고 분명히 어딘가에서 망쳐 놨습니다. 가능하다면 나는 그 눈이 좋지 않게 최적화 된 if 문을 사용하는 대신 코드를 최소화 할 수있는 방법은 무엇입니까?도와주세요. while 루프에서 뭔가 묻는 데 문제가 있습니다.
public static void main(String[]args)
{
//Number 1
Scanner scan = new Scanner(System.in);
int num = 0;
int num2 = 0;
int num3 = 0;
int count = 2;
String yesno;
do
{
System.out.println("Which aircraft would you like to simulate?");
System.out.println("1. Blimp");
System.out.println("2. Helicopter");
System.out.println("3. Fighter Jet");
System.out.println("4. Space Shuttle");
num = scan.nextInt();
if(num<1 || num>4) {System.out.println("Invalid");}
}
while(num<1 || num>4);
do
{
System.out.println("What characteristics would you like? (Input one, then the other)");
System.out.println("1. Position Trim ");
System.out.println("2. Force Breakout");
System.out.println("3. Force Gradient");
System.out.println("4. Force Friction");
System.out.println("5. Damping");
System.out.println("6. Hard Stop");
num2 = scan.nextInt();
num3 = scan.nextInt();
if(num2 == 1 || num3 == 1)
{
System.out.println("The position to which a flight control returns");
}
if(num2 == 2 ||num3 == 2)
{
System.out.println("A force that returns a control to Trim. This is a constant force applied toward Trim which remains the same despite how far the control is moved (displacement) and how fast a control is moved (velocity).");
}
if(num2 == 3 || num3 == 3)
{
System.out.println("A force that returns a control to Trim, but one that varies with displacement. The farther the control is moved, the stronger the force applied toward trim.");
}
if (num2 == 4 || num3 == 4)
{
System.out.println("A constant force that is opposite to the direction of movement");
}
if(num2 == 5 || num3 == 5)
{
System.out.println("A force that is oppisite to the direction of movement. Damping varies with velocity. The faster a control is moved the stronger the force.");
}
if (num2 == 6 || num3 == 6)
{
System.out.println("A force that simulates a mechanical limit of travel. By varying the Hard Stops, the range of travel can be adjusted");
}
if(num2 < 1 || num2 > 6)
{
System.out.println("Invalid input");
}
if (yesno.equalsIgnoreCase("y")) {
do
{
System.out.println("What characteristics would you like? (Input one, then the other)");
System.out.println("1. Position Trim ");
System.out.println("2. Force Breakout");
System.out.println("3. Force Gradient");
System.out.println("4. Force Friction");
System.out.println("5. Damping");
System.out.println("6. Hard Stop");
num2 = scan.nextInt();
num3 = scan.nextInt();
if(num2 == 1 || num3 == 1)
{
System.out.println("The position to which a flight control returns");
}
if(num2 == 2 ||num3 == 2)
{
System.out.println("A force that returns a control to Trim. This is a constant force applied toward Trim which remains the same despite how far the control is moved (displacement) and how fast a control is moved (velocity).");
}
if(num2 == 3 || num3 == 3)
{
System.out.println("A force that returns a control to Trim, but one that varies with displacement. The farther the control is moved, the stronger the force applied toward trim.");
}
if (num2 == 4 || num3 == 4)
{
System.out.println("A constant force that is opposite to the direction of movement");
}
if(num2 == 5 || num3 == 5)
{
System.out.println("A force that is oppisite to the direction of movement. Damping varies with velocity. The faster a control is moved the stronger the force.");
}
if (num2 == 6 || num3 == 6)
{
System.out.println("A force that simulates a mechanical limit of travel. By varying the Hard Stops, the range of travel can be adjusted");
}
if(num2 < 1 || num2 > 6)
{
System.out.println("Invalid input");
}
System.out.println("Would you like to re-select?(Y/N)");
yesno = scan.nextLine();
count += 2;
}
while(num2 < 1 || num2 > 6 || num3 < 1 ||num3 > 6);
}
else if (yesno.equalsIgnoreCase("n"))
{
System.out.println("You've used " + count + " characteristics");
}
}
while(num2 < 1 || num2 > 6 || num3 < 1 ||num3 > 6);
}
}
출력은 얼마나됩니까? –
'yesno'를 읽거나 설정하려고하는 코드는 어디에 있습니까? 나는 줄에 문제가있는 것 같아요.'yesno'는 대기열에 남아있는 \ n을 읽습니다. – John3136
내가 얻으려고하는 것은 예 또는 아니오라는 질문이고 특성 선택으로 돌아갑니다. – user3466743