코드에 코어 데이터가 있는데, 왜 코드 루프 11 라운드 이하입니까?왜이 루프가 열 번입니까?
- (void)testingDBmodel {
NSLog(@">>testingDBmodel<<");
//=================DATABASE===================//
// id
// qDiff
// question
// qRightAnswer
// qWrongAnswer1
// qWrongAnswer2
// qNr
// qRegDate
if (managedObjectContext == nil) { managedObjectContext = [(FamQuiz_v2AppDelegate *)
[[UIApplication sharedApplication] delegate] managedObjectContext]; }
NSManagedObjectContext *context = [self managedObjectContext];
NSManagedObject *famQuizInfo = [NSEntityDescription
insertNewObjectForEntityForName:@"questions"
inManagedObjectContext:context];
[famQuizInfo setValue:[NSNumber numberWithInt:1] forKey:@"idQ"];
[famQuizInfo setValue:@"qDiff1" forKey:@"qDiff"];
[famQuizInfo setValue:@"question1" forKey:@"question"];
[famQuizInfo setValue:@"qRightAnswer1" forKey:@"qRightAnswer"];
[famQuizInfo setValue:@"qWrongAnswer1_1" forKey:@"qWrongAnswer1"];
[famQuizInfo setValue:@"qWrongAnswer2_2" forKey:@"qWrongAnswer2"];
[famQuizInfo setValue:@"999" forKey:@"qNr"];
[famQuizInfo setValue:[NSDate date] forKey:@"qRegDate"];
NSError *error;
if (![context save:&error]) {
NSLog(@"Whoops, couldn't save: %@", [error localizedDescription]);
}
//==========READ DATABASE==============//
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription
entityForName:@"questions" inManagedObjectContext:context];
[fetchRequest setEntity:entity];
NSArray *fetchedObjects = [context executeFetchRequest:fetchRequest error:&error];
NSLog(@"\n \n");
NSLog(@"\n \n");
// NSLog (@ "fetchObjects 번호 : % I", [fetchedObjects.count]) 여기서
for (NSManagedObject *info in fetchedObjects) {
xx = xx + 1;
NSLog(@"\n \n");
NSLog(@"id: %i", [[info valueForKey:@"idQ"] intValue]);
NSLog(@"qDiff: %@", [info valueForKey:@"qDiff"]);
NSLog(@"question: %@", [info valueForKey:@"question"]);
NSLog(@"qRightAnswer: %@", [info valueForKey:@"qRightAnswer"]);
NSLog(@"qWrongAnswer1: %@", [info valueForKey:@"qWrongAnswer1"]);
NSLog(@"qWrongAnswer2: %@", [info valueForKey:@"qWrongAnswer2"]);
NSLog(@"qNr: %@", [info valueForKey:@"qNr"]);
NSLog(@"qRegDate: %@", [info valueForKey:@"qRegDate"]);
NSLog(@"\n \n");
NSLog(@"nr: %i", xx);
}
코드이고; NSLog (@ "\ n \ n"); NSLog (@ "fetchedObjects : % @", fetchedObjects); NSLog (@ "\ n \ n");
2010-12-03 17 : 37 :
int xx = 0; // just to see how many loops for (NSManagedObject *info in fetchedObjects) { xx = xx + 1; NSLog(@"\n \n"); NSLog(@"id: %i", [[info valueForKey:@"idQ"] intValue]); NSLog(@"qDiff: %@", [info valueForKey:@"qDiff"]); NSLog(@"question: %@", [info valueForKey:@"question"]); NSLog(@"qRightAnswer: %@", [info valueForKey:@"qRightAnswer"]); NSLog(@"qWrongAnswer1: %@", [info valueForKey:@"qWrongAnswer1"]); NSLog(@"qWrongAnswer2: %@", [info valueForKey:@"qWrongAnswer2"]); NSLog(@"qNr: %@", [info valueForKey:@"qNr"]); NSLog(@"qRegDate: %@", [info valueForKey:@"qRegDate"]); NSLog(@"\n \n"); NSLog(@"nr: %i", xx); } [fetchRequest release]; //NSError* error; if(![[famQuizInfo managedObjectContext] save:&error]) { NSLog(@"Failed to save to data store: %@", [error localizedDescription]); NSArray* detailedErrors = [[error userInfo] objectForKey:NSDetailedErrorsKey]; if(detailedErrors != nil && [detailedErrors count] > 0) { for(NSError* detailedError in detailedErrors) { NSLog(@" DetailedError: %@", [detailedError userInfo]); } } else { NSLog(@" %@", [error userInfo]); } }
} 여기
출력의 마지막 두 루프 인 51.962 Test_v2 [11,965 : 207] ID : 1
2010- 12-03 17 : 37 : 51.963 Test_v2 [11965 : 207] qDiff : qDiff1
2010-12-03 17 : 37 : 51.964 Test_v2 [11965 : 207] 질문 : 질문 1
2010-12-03 17 : 37 : 51.964 Test_v2 [11965 : 207] qRightAnswer : qRightAnswer1,453,210 2010-12-03 17 : 37 : 207 11,965] qWrongAnswer1 : qWrongAnswer1_1
2010-12-03 17 : 37 : 51.965 Test_v2 [11,965 : 207] qWrongAnswer2 : qWrongAnswer2_2
2010-12-03 17 51.964 Test_v2 : 37 : 51.966 Test_v2 [11965 : 207] qNr : 999
2010-12-03 17 : 37 : 51.967 Test_v2 [11965 : 207] qRegDate : 2010-12-03 17:36:12 +0100
2010-12 37 : 17 -03 51.967 Test_v2 37 :
2010-12-03 17 11,965 207]
Test_v2 51.973 [11,965 : 207] NR : 102010-12-03 17 : 37 : 51.973 Test_v2 [11965 : 207] :
2010-12-03 17 363,210 Test_v2 51.974 [11,965 : 207] ID : 1
2010-12-03 17 : 37 : 51.974 Test_v2 [11,965 : 207] qDiff : qDiff1
2010-12-03 17 : 37 : 51.975 Test_v2 [11965 : 207] question : question1
2010-12-03 17:37:51.976 qRightAnswer : qRightAnswer1
2010-12-03 17 : 37 : 51.976 Test_v2 [11965 207] qWrongAnswer1 : qWrongAnswer1_1
2010-12-03 17 : 37 : 51.977 Test_v2 [11,965 : 207] qWrongAnswer2 : qWrongAnswer2_2
2010-12-03 17 : 37 : 51.977 Test_v2 [11,965 : 207] qNr 999
2010-12-03 17 : 37 : 51.978 Test_v2 [11965 : 207] qRegDate : 2010-12-03 17 : 3 37 : +0100
2010-12-03 17 7시 51분 Test_v2 51.978 [11,965 : 207]
이 질문에 더 많은 편집이 필요하다고 생각합니다. 가져 오는 개체에 대한 정보입니다. – Eiko
루핑중인 코드는 무엇입니까? 데이터베이스에서 반환되는 객체를 통해 실행되는 LOOP가 있으며 객체 컨텍스트에 현재 얼마나 많은 항목이 있습니까? – DerekH