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내가 여기, 코드를 이해하려고 노력하고 혼란을 조각의 원인이되는 :단항 포인터 증가는
typedef map<int, Person, less<int> > people_map;
people_map people;
.
.
.
cout << "Erasing people of age 100" << endl;
for (people_map::iterator j = people.begin(); j != people.end();) {
if (j->second.GetAge() == 100)
{
people.erase(j++); // iterator is advanced before the erase occurs
}
else
++j; // advance the iterator
} // end of erase loop
혼란은 다음과 같습니다 난 후 J를 증가하려면 세그먼트 화 오류를 일으키는 함수 호출. 나는 이런 식으로 변경
:
if (j->second.GetAge() == 100)
{
temp = j++;
j--;
people.erase(j); // iterator is advanced before the erase occurs
j=temp;
}
원인이 오류를 세그멘테이션 이유를 이해할 수 없습니다입니다.
또는 같은
:if (j->second.GetAge() == 100)
{
people.erase(j); // iterator is advanced before the erase occurs
j++;
}
는 세그먼트 오류가 발생합니다. 후위 증가를 사용하는 이유는,
이// disable warnings about long names
#ifdef WIN32
#pragma warning(disable : 4786)
#endif
#include <string>
#include <map>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <iterator>
#include <functional>
using namespace std;
class Person {
// private members
string m_sName;
string m_sEmail;
int m_iAge;
public:
// constructor
Person(const string sName,
const string sEmail,
const int iAge) :
m_sName(sName), m_sEmail(sEmail), m_iAge(iAge) {
};
// default constructor
Person() : m_iAge(0) {
};
// copy constructor
Person(const Person & p) :
m_sName(p.m_sName), m_sEmail(p.m_sEmail), m_iAge(p.m_iAge) {
};
// operator =
Person & operator=(const Person & rhs) {
// don't assign to self
if (this == &rhs)
return *this;
m_sName = rhs.m_sName;
m_sEmail = rhs.m_sEmail;
m_iAge = rhs.m_iAge;
return *this;
};
// access private members
string GetName() const {
return m_sName;
};
string GetEmail() const {
return m_sEmail;
};
int GetAge() const {
return m_iAge;
};
}; // end of class Person
// function object to print one person
class fPrint {
ostream & m_os;
public:
// constructor - remember which stream to use
fPrint(ostream & os) : m_os(os) {
};
// person object arrives as a pair of key,object
void operator() (const pair <const int, const Person> & item) const {
m_os << "# " << item.first << " - name: "
<< item.second.GetName()
<< " - " << item.second.GetEmail()
<< ", age " << item.second.GetAge()
<< endl;
};
}; // end of class fPrint
// declare type for storing people (numeric key, person object)
typedef map<int, Person, less<int> > people_map;
int main(void) {
// make a map of people
people_map people;
// add items to list
people [1234] = Person("Nick", "[email protected]", 15);
people [4422] = Person("Fred", "[email protected]", 100);
people [88] = Person("John", "[email protected]", 35);
// insert a different way ...
people.insert(make_pair(42, Person("Abigail", "[email protected]", 22)));
// best to declare this on its own line :)
fPrint fo(cout); // instance of function output object
// print everyone (calls a function object to print)
cout << "Printing all using fPrint ..." << endl;
for_each(people.begin(), people.end(), fo);
// find someone by key
cout << "Finding person 4422 ..." << endl;
people_map::const_iterator i = people.find(4422);
if (i == people.end())
cout << "Not found." << endl;
else {
fo(*i); // dereference and print
// another way of printing -
// key itself is the "first" part of the map pair ...
cout << "Found key = " << i->first << endl;
// person object is the "second" part of the map pair...
cout << "Found name = " << i->second.GetName() << endl;
}
// Note, this will not work:
// fPrint (cout) (*i);
// However this will:
// 0, fPrint (cout) (*i);
// However I think the extra zero is a bit obscure. :)
// An alternative way of finding someone.
// Note - this will add them if they are not there.
// Since this is a reference changing it will change the person in the
// map. Leave off the & to get a copy of the person.
Person & p = people [1234];
cout << "Person 1234 has name " << p.GetName() << endl;
// Example of erasing an element correctly ...
// If we did the j++ as part of the for loop we would end up
// adding 1 to an iterator that pointed to an element that was
// removed which would lead to a crash. See Josuttis p 205.
cout << "Erasing people of age 100" << endl;
for (people_map::iterator j = people.begin(); j != people.end();) {
if (j->second.GetAge() == 100)
{
people.erase(j++); // iterator is advanced before the erase occurs
}
else
++j; // advance the iterator
} // end of erase loop
// now display who is left
cout << "Printing people left after erase ..." << endl;
for_each(people.begin(), people.end(), fo);
return 0;
} // end of main
:
나는 후행 증가의 임시 결과를 사용하지 않는 것을 제외하고, 기능적으로 작동 코드와 동일하다, 당신은 또한 다음과 같이 그것을 할 수도있을 것 같군요 http://stackoverflow.com/questions/596162/can-you-remove-elements-from-a-stdlist-while-iterating-through-it – Anna