SQL : 섹션별로 그룹화 된 쿼리에서 하위 쿼리를 어떻게 사용할 수 있습니까?

Question

섹션별로 그룹화 된 쿼리에서 하위 쿼리를 어떻게 사용할 수 있습니까?

select 
    t1.sen, 
    sum(t1.d1)as d1, 
    sum(t1.d2)as d2, 
    sum(t1.d1+t1.d2) as d_sum, 
    Round((sum((1000*(t1.d1+t1.d2))/(9500-(
     select sum(t2.t_shab+t2.t_rooz) 
     from tbl1 t2 
     where FCode=81 AND DCode=1 AND t2.sen<=t1.sen 
    )))),1) as SSS 
from 
    tbl1 t1 
where 
    FCode = 81 
    AND DCode = 1 

그룹 t1.sen

Answer 1

그 진정한 방법

create function getSumBSen2(@pfcode INT, @pdcode INT, @pSen INT) returns int 
as 
begin 
    declare @r int; 
    select 
     @r= sum(t2.t_shab + t2.t_rooz) 
    from 
     tbl1 t2 
    where 
     t2.FCode = @pfcode 
    and t2.DCode = @pdcode 
    and t2.sen <= @pSen; 

    return (@r); 
end; 
GO 

select 
    t1.sen, 
    sum(t1.d1) as d1, 
    sum(t1.d2) as d2, 
    sum(t1.d1 + t1.d2) as d_sum, 
    Round((sum((1000*(t1.d1+t1.d2)+0.01)/(9500-(dbo.getSumBSen2(t1.FCode, t1.DCode, t1.sen))))),1) as SSS 
from 
    tbl1 t1 
where 
    t1.FCode = 81 
and t1.DCode = 1 
group by 
    t1.sen; 

Answer 2

의 :이 쿼리처럼

Cannot perform an aggregate function on an expression 
containing an aggregate or a sub query. 

:

나는 SQL 서버 2008 R2와 델파이 2010

나는이 오류가 사용 보증이 없으면 시도해 볼 수 있습니다. 작동하지 않는 경우 알려 주시면

create function getSumBSen(@pfcode number, @pdcode number, @pSen number) returns number 
as 

begin 
    declare @r number; 
    select 
     @r =sum(t2.t_shab + t2.t_rooz) 
    from 
     tbl1 t2 
    where 
     t2.FCode = @pfcode 
    and t2.DCode = @pdcode 
    and t2.sen <= @pSen 
    group by t2.FCode, t2.DCode; 

    return (@r); 
end; 


select 
    t1.sen, 
    sum(t1.d1) as d1, 
    sum(t1.d2) as d2, 
    sum(t1.d1 + t1.d2) as d_sum, 
    Round((sum((1000*(t1.d1+t1.d2))/(9500-getSumBSen(t1.FCode, t1.dcode, t1.sen)))),1) as SSS 
from 
    tbl1 t1 
where 
    t1.FCode = 81 
and t1.DCode = 1 
group by 
    t1.sen; 

유품 답변 :

• Function creation

추가, 내 편집이 너무 짧기 때문에 내가 실제로 코드를 수정하지 않습니다. 그래서 코드 픽스 (code fix)를 받아 들일 수 있도록 잡다한 잡동사니를 써야했다.

Answer 3

이 시도 :

DECLARE @tbl1 AS TABLE 
    (
    FCode INT 
    ,DCode INT 
    ,sen INT 
    ,d1 INT 
    ,d2 INT 
    ,t_shab INT 
    ,t_rooz INT 
    ) ; 

SELECT * 
FROM (
     SELECT t1.sen 
       ,SUM(t1.d1) AS d1 
       ,SUM(t1.d2) AS d2 
       ,SUM(t1.d1 + t1.d2) AS d_sum 
       ,ROUND((SUM((1000 * (t1.d1 + t1.d2))/(9500 - factor.factor))), 
         1) AS SSS 
     FROM @tbl1 AS t1 
     INNER JOIN (
        SELECT t1.sen 
          ,SUM(t2.t_shab + t2.t_rooz) AS factor 
        FROM @tbl1 AS t2 
        INNER JOIN @tbl1 AS t1 
          ON t1.FCode = 81 
           AND t1.DCode = 1 
           AND t2.FCode = 81 
           AND t2.DCode = 1 
           AND t2.sen <= t1.sen 
        GROUP BY t1.sen 
        ) AS factor 
       ON factor.sen = t1.sen 
     WHERE FCode = 81 
       AND DCode = 1 
     GROUP BY t1.sen 
     ) AS X ; 

Answer 4

당신이 일반적인 패턴 다음, FROM 절 아래에 하위 쿼리를 넣을 수 있어야한다 :

SELECT TABLE1.ID, SUM(TABLE1.A), ROUND(SUM(T2.B1), 2) 
FROM TABLE1, (SELECT SUM(B) B1 FROM TABLE2 WHERE ...) T2 
GROUP BY TABLE1.ID 

쿼리를 "번역"시도를, 당신 ' 아마 이것과 비슷한 것을 얻을 것입니다 :

select 
    t1.sen, 
    sum(t1.d1)as d1, 
    sum(t1.d2)as d2, 
    sum(t1.d1+t1.d2) as d_sum, 
    Round((sum((1000*(t1.d1+t1.d2))/(9500-(
     t2a.s 
    )))),1) as SSS 
from 
    tbl1 t1, 
    (
     select sum(t2.t_shab+t2.t_rooz) s 
     from tbl1 t2 
     where FCode=81 AND DCode=1 AND t2.sen<=t1.sen 
    ) t2a 
where 
    FCode = 81 
    AND DCode = 1 
group by 
    t1.sen