필터 SQL 결과?

Question

난 상태 3과 1에서 같은 이메일을 받았습니다 상태 3의 페이지에서 저를 보여주고 나 또한 여기에

상태 1로 그 이메일을 보내에만이 쿼리 상태 3 의 이메일을 보여줄 필요가 나의 쿼리입니다 :

둘 다 내부 조인과 왼쪽 가입 혼합 한

SELECT live_customers.Id, live_customers.date, 
     live_customers.firstname, live_customers.lastname, live_customers.phone, 
     live_customers.phone2, live_customers.email, live_customers.num_sellers, 
     live_customers.sell_date,live_customers.public_description, 
     live_customers.public_image, live_customers.price, 
     live_customers.takanon, live_customers.confirm_mail_sent, live_customers.paid, 
     live_customers.shirt_size, live_customers.shirt_size_extra, 
     live_customers.stand_rent, live_customers.refunded, live_customers.call1, 
     live_customers.call2, live_customers.notes, 
     live_customers.auth_number, live_customers.hasContact, live_customers.IP, 
     live_customers.status, live_status.name AS StatusName, 
     live_status.color AS StatusColor, live_compound.name AS CompoundName 
    FROM live_customers 
     INNER JOIN live_status 
        ON live_status.Id=live_customers.status   
     INNER JOIN 
     LEFT JOIN live_compound 
        ON live_compound.Id=live_customers.compound_id 
    WHERE live_customers.status='3'       
    GROUP BY 
     live_customers.Id 
    ORDER BY 
     live_customers.Id DESC 
    LIMIT 0,30 

Answer 1

...

이

SELECT live_customers.Id, live_customers.date, 
     live_customers.firstname, live_customers.lastname, live_customers.phone, 
     live_customers.phone2, live_customers.email, live_customers.num_sellers, 
     live_customers.sell_date,live_customers.public_description, 
     live_customers.public_image, live_customers.price, 
     live_customers.takanon, live_customers.confirm_mail_sent, live_customers.paid, 
     live_customers.shirt_size, live_customers.shirt_size_extra, 
     live_customers.stand_rent, live_customers.refunded, live_customers.call1, 
     live_customers.call2, live_customers.notes, 
     live_customers.auth_number, live_customers.hasContact, live_customers.IP, 
     live_customers.status, live_status.name AS StatusName, 
     live_status.color AS StatusColor, live_compound.name AS CompoundName 
    FROM live_customers 
     INNER JOIN live_status 
        ON live_status.Id=live_customers.status   
     INNER JOIN live_compound 
        ON live_compound.Id=live_customers.compound_id 
    WHERE live_customers.status='3'       
    GROUP BY 
     live_customers.Id 
    ORDER BY 
     live_customers.Id DESC 
    LIMIT 0,30 

Answer 2

내가 졸을 발견하십시오 내 문제의 ution. 여기있어. 이에게 유용 희망은 어떤 하나

SELECT live_customers.Id, live_customers.date, 
      live_customers.firstname, live_customers.lastname, live_customers.phone, 
      live_customers.phone2, live_customers.email, live_customers.num_sellers, 
      live_customers.sell_date,live_customers.public_description, 
      live_customers.public_image, live_customers.price, 
      live_customers.takanon, live_customers.confirm_mail_sent, live_customers.paid, 
      live_customers.shirt_size, live_customers.shirt_size_extra, 
      live_customers.stand_rent, live_customers.refunded, live_customers.call1, 
      live_customers.call2, live_customers.notes, 
      live_customers.auth_number, live_customers.hasContact, live_customers.IP, 
      live_customers.status, live_status.name AS StatusName, 
      live_status.color AS StatusColor, live_compound.name AS CompoundName 
    FROM live_customers 
     INNER JOIN live_status 
       ON live_status.Id=live_customers.status   
     INNER JOIN live_compound 
       ON live_compound.Id=live_customers.compound_id     

     WHERE live_customers.status='3' 
     AND live_customers.Email NOT IN (SELECT Email FROM live_customers WHERE status=1)     
     GROUP BY 
    live_customers.Id 
     ORDER BY 
    live_customers.Id DESC