저는 macOS Sierra에서 Python 3을 실행 중이며 특정 단어의 동의어로 구성된 문장을 만들어야합니다. 이렇게하려면 PyDictionary를 사용하고 있습니다.PyDictionary/BeautifulSoup 문제
그러나 아래 코드에서 코드를 실행할 때 오류 (Python 인터프리터)와 경고 (BeautifulSoup)가 표시됩니다.
출력 :
/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/site-packages/beautifulsoup4-4.5.3-py3.5.egg/bs4/__init__.py:181: UserWarning: No parser was e
xplicitly specified, so I'm using the best available HTML parser for this system ("html.parser"). This usually isn't a problem, but if you run this code on an
other system, or in a different virtual environment, it may use a different parser and behave differently.
The code that caused this warning is on line 53 of the file main.py. To get rid of this warning, change code that looks like this:
BeautifulSoup([your markup])
to this:
BeautifulSoup([your markup], "html.parser")
markup_type=markup_type))
Traceback (most recent call last):
File "main.py", line 53, in <module>
edison()
File "main.py", line 29, in edison
say(respond(["I", "am", "happy", "to", "hear", "that", "html.parser"]) + "!")
File "/path/to/code/respond.py", line 9, in respond
output = (output + " " + (random.choice(dictionary.synonym(word, "html.parser"))))
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/random.py", line 265, in choice
return seq[i]
KeyError: 0
main.py :이
from respond import *
def edison():
mood = input("Hi, " + username + "! How are you today? ")
if mood.lower() in definitions.positive:
print(respond(["I", "am", "happy", "to", "hear", "that", "html.parser"]) + "!") #This is line 29
elif mood.lower() in definitions.negative:
print(respond(["I", "am", "sorry", "to", "hear", "that", "html.parser"]) + "!")
edison() #This is line 53
respond.py :
import random
from PyDictionary import PyDictionary
dictionary = PyDictionary()
def respond(wordList):
output = ""
for word in wordList:
output = (output + " " + (random.choice(dictionary.synonym(word, "html.parser"))))
return output
왜이 지구상에는 아름다운 스프가 있습니까? 뭔가를 포함시키지 않았습니까? – Elodin
나 자신이 BeautifulSoup을 사용하지 않고있다. 그러나 Python Package Index PyDictionary에 의하면 그것을 사용하고있다. https://pypi.python.org/pypi/PyDictionary –