루프의 배열에 배열을 작성하십시오.

Question

이것은 내 코드입니다! 나는 배열 $test에서 얻으려고 노력하고 끝내 날 $final처럼 보여줘! 도움이 tnx! 코드는 도메인 이름을 얻고 사용자 ID가 반복 된 시간을 표시해야합니다!

<?php 

$test = array(
array(
    'id' => 1, 
    'domain' => 'google.com', 
    'userid' => "123" 
), 
array(
    'id' => 2, 
    'domain' => 'google.com', 
    'userid' => "456"enter 
), 
array(
    'id' => 3, 
    'domain' => 'yahoo.com', 
    'userid' => "456" 
), 
array(
    'id' => 4, 
    'domain' => 'google.com', 
    'userid' => "123" 
), 
array(
    'id' => 5, 
    'domain' => 'bing.com', 
    'userid' => "128" 
) 
); 
$i=0; 
foreach ($test as $items) { 
$domains[$i]=$items['domain']; 
$userid[$i]=$items['userid']; 
$i++; 
} 
$domain=array_unique($domains); 
$domain1 = array_values($domain); 
print_r($domain); 
echo '<pre>'; 
print_r($test); 
echo '</pre>'; 
echo '<hr>'; 
$d=1; $tedad = 1; 
while($d<=4){ 
    $b = 1 ; $c=0; 
    while ($test[$b]['id']<=4) { 
     if($test[$b]['domain'] == $domain1[$d]) 
     { 
      $temp = $test[$b]['userid']; 
      if(/*$test[$b]['userid'] !==*/ !array_key_exists($domain1[$d] ['userid']){ 
       //$domain1[$d] = array($test[$b]['userid'] => $tedad) ; 
       echo $temp; 
       $end = array(
       $domain1[$d] => array(
       $temp => $tedad) 
       ); 

      } 
      else{ 
       $end[$d][$test[$b]['userid']]= $end[$d][$test[$b]['userid']] +1; 

     } 
     } 
     else{ 
      $b++; 

     } 

} 
    $d++; $tedad = 1; 
} 

print_r($end); 
$final = array(
"google.com" => array(
    "123" => 2, 
    "456" => 1 
), 
"yahoo.com" => array(
    "456" => 1 
) 
); 
echo '<pre>'; 
print_r($final); 
echo '</pre>'; 
echo '<hr>'; 

?> 

Answer 1

<?php 

$test = array(
array(
    'id' => 1, 
    'domain' => 'google.com', 
    'userid' => "123" 
), 
array(
    'id' => 2, 
    'domain' => 'google.com', 
    'userid' => "456" 
), 
array(
    'id' => 3, 
    'domain' => 'yahoo.com', 
    'userid' => "456" 
), 
array(
    'id' => 4, 
    'domain' => 'google.com', 
    'userid' => "123" 
) 
); 

echo '<pre>'; 
print_r($test); 
echo '</pre>'; 
echo '<hr>'; 

$domains = array(); 
foreach ($test as $value) { 
if (!in_array($value['domain'], $domains)) 
    $domains[$value['domain']] = array(); 
} 
foreach ($domains as $key => $domain) { 
foreach ($test as $item) { 
    if ($key == $item['domain']) { 
     if (isset($domains[$key][$item['userid']])) { 
      $domains[$key][$item['userid']] = $domains[$key]  [$item['userid']]+1; 
     } else { 
      $domains[$key][$item['userid']] = 1; 
     } 
    } 
    } 
    } 

    echo '<pre>'; 
    print_r($domains); 
echo '</pre>'; 
    echo '<hr>'; 

    // $final = array(
//  "google.com" => array(
    //  "123" => 2, 
    //  "456" => 1 
    // ), 
    // "yahoo.com" => array(
//   "456" => 1 
// ) 
//); 

    // echo '<pre>'; 
// print_r($final); 
// echo '</pre>'; 
// echo '<hr>'; 
?> 

Answer 2

시도 :

$result = array(); 
foreach($test as $t) 
{ 
    if(isset($result[$t['domain']][$t['userid']])) 
     $result[$t['domain']][$t['userid']]++; 
    else $result[$t['domain']][$t['userid']] = 1; 
} 

일부 도메인처럼 사용 포함하지 않는 경우 :

$result = array(); 
foreach($test as $t) 
{ 
    if($t['domain'] == 'bing.com') 
     continue; 

    if(isset($result[$t['domain']][$t['userid']])) 
     $result[$t['domain']][$t['userid']]++; 
    else $result[$t['domain']][$t['userid']] = 1; 
}