안녕하세요,
내가 할 수있는 방법
$ar = array_filter($ar, function($el) {
$search = 'New York';
$name = $ar['name'];
$potentialNumber = substr($name, strlen($search));
return ((substr($name, 0, strlen($search)) == $search) && // starts with NY
($potentialNumber == '' || is_numeric($potentialNumber)); // [0-9]*
});
PHP 5.3 전에?
오전해야 : //stackoverflow.com/questions/3694620/anonymous-functions-pre-php-5-3-0) – Gordon
* (참고) * [PHP 언어의 콜백] (http://de2.php.net/manual /en/language.pseudo-types.php#language.types.callback) – Gordon