Return joined 테이블

Question

내 도메인 컨텍스트에 대해이 linq 쿼리를 입력했는데 왜 tblaptmt에서 두 테이블 일치 학생 ID의 데이터를 검색하지 못했습니다?

public IQueryable<StudentViewAppointment> StudentViewAppointments(string StuId) 
    { 
     //IQueryable<StudentViewAppointment> studentViewAppointments = 
     //from aptmt in this.ObjectContext.tblaptmts join ch in 
     //aptmt.consultationID equals ch.consultationID where aptmt.studentID == StuId 
     //select aptmt; 
     //return studentViewAppointments as IQueryable<StudentViewAppointment>; 

     return ObjectContext.tblaptmts.Where(a => a.studentID == StuId).Join 
     (ObjectContext.tblConsultationHours, a => a.consultationID, 
     ch => ch.consultationID, (a, ch) => 
      new StudentViewAppointment() 
       { 
        AppointmentId = a.aptmtID, 
        Apremark = a.apremark, 
        APstatus = a.apstatus, 
        APsubject = a.apsubject, 
        ConsultationId = a.consultationID, 
        Day = ch.cday, 
        StartTime = (DateTime)ch.cstartTime, 
        EndTime = (DateTime)ch.cendTime, 
        LectureId = ch.lecturerID, 
        StudentId = a.studentID 
       }); 
    } 

도메인 서비스 클래스. CS

public partial class StudentViewAppointment 
{ 
    [Key] 
    public int AppointmentId { get; set; } 
    public string Apremark { get; set; } 
    public string APsubject { get; set; } 
    public string APstatus { get; set; } 
    public int ConsultationId { get; set; } 
    public string StudentId { get; set; } 
    public string Venue { get; set; } 
    public DateTime StartTime { get; set; } 
    public DateTime EndTime { get; set; } 
    public string LectureId { get; set; } 
    public string Day { set; get; } 
} 

도메인 서비스 클래스 Metadata.cs

dgSlot.ItemsSource = context.StudentViewAppointments; 
context.Load(context.StudentViewAppointmentsQuery("TP123123")); 

Datagrid.xaml.cs

Answer 1

return (from a in ObjectContext.tblaptmts 
     join ch in ObjectContext.tblConsultationHours 
      on a.consultationID equals ch.consultationID 
     where a.studentID == StuId 
     select new StudentViewAppointment() 
        {      
         AppointmentId = a.aptmtID, 
         Apremark = a.apremark, 
         ----- 
         ----- 
        });