PHP - 치명적 오류 : 비 객체의 super_query() 멤버 함수 호출

Question

치명적 오류 : /mp3.is-great.org/htdocs/modules에없는 객체의 super_query() 멤버 함수를 호출하십시오.

<?php 

if(isset($_REQUEST['username'])) $username = $_REQUEST['username']; 

if(!$username) die("User not found!"); 

$user = $db->super_query("SELECT username, user_id, lastdate, reg_date, banned, info, foto, fullname, playlist, song FROM tan_users WHERE username = '$username'"); 

if(!$user) die("User not found!"); 

$row = $db->super_query("SELECT COUNT(*) AS count FROM tan_favorites WHERE user_id = '" . $user['user_id'] . "'"); 
$user['favorites'] = $row['count']; 

$row = $db->super_query("SELECT COUNT(*) AS count FROM tan_playlists WHERE user_id = '" . $user['user_id'] . "'"); 
$user['playlists'] = $row['count']; 


$smarty->assign("User", $user); 

$action = $_REQUEST['action']; 

$smarty->assign("Action", $action); 

if($action == 'favorites'){ 

    $db->query("SELECT source, hash, name FROM tan_favorites WHERE user_id = '" . $user['user_id'] . "'"); 

    while ($row = $db->get_row($sql_result)){ 

     $row['play_url'] = play_url($row['hash'], $row['source'], $row['name']); 

     $favorites[] = $row; 

    } 

    $smarty->assign('Favorites', $favorites); 

}elseif($action == 'playlists'){ 

    $db->query("SELECT tan_playlists.id, tan_playlists.foto, tan_playlists.name, tan_users.username, tan_users.fullname FROM tan_playlists LEFT JOIN tan_users ON tan_playlists.user_id = tan_users.user_id WHERE tan_playlists.user_id = '" . $user['user_id'] . "'"); 

    while ($row = $db->get_row($sql_result)){ 

     $playlists[] = $row; 

    } 

    $smarty->assign('Playlists', $playlists); 

}else{ 

    $db->query("SELECT source, hash, name FROM tan_favorites WHERE user_id = '" . $user['user_id'] . "' LIMIT 0,10"); 

    while ($row = $db->get_row($sql_result)){ 

     $row['play_url'] = play_url($row['hash'], $row['source'], $row['name']); 

     $favorites[] = $row; 

    } 

    $smarty->assign('Favorites', $favorites); 

    $db->query("SELECT tan_playlists.id, tan_playlists.foto, tan_playlists.name, tan_users.username, tan_users.fullname FROM tan_playlists LEFT JOIN tan_users ON tan_playlists.user_id = tan_users.user_id WHERE tan_playlists.user_id = '" . $user['user_id'] . "' ORDER by id DESC LIMIT 0,10"); 

    while ($row = $db->get_row($sql_result)){ 

     $playlists[] = $row; 

    } 

    $smarty->assign('Playlists', $playlists); 

} 

$smarty->assign("Title", $username); 

if($member_id['username'] == $username) $smarty->assign("MEMBER", $member_id); 

?> 

어떤 아이디어가 왜이 오류가 될 것입니다 :

이 내 profile.php입니다 라인 7 /profile.php?

안전 모드 내 호스팅에 꺼져, 그것은 무료 호스트 그래서 내가 좀 PHP는 멍청한 놈, 내 문제를 해결하기 위해 어떤 도움과 링크를 감상 할 수있어

의 php.ini 변경할 수 있습니다.

Answer 1

$db 개체를 만들지 않은 것 같습니다.

Answer 2

먼저 당신이

$db = new PDO('host'; 'table', 'user', 'pass');