Sql 두 개의 셀을 결합하십시오.

Question

이것은 쉬운 것이어야합니다. 여기 내 문입니다 :

Select UP1.PropertyValue as QuestionOption, email +'; ' as QuestionOptionValue 
    from Users 
INNER JOIN UserProfile UP1 
on UP1.UserId = Users.UserId AND PropertyDefinitionID = (SELECT PropertyDefinitionID 
    FROM ProfilePropertyDefinition Where PropertyName='Committee' and 
    PropertyValue='Beach and Recreation' AND PortalID=0) 

그리고 반환

QuestionOption   QuestionOptionValue 
Beach and Recreation  eamil@gmail.com; 
Beach and Recreation  email@AOL.COM; 

가 나는

QuestionOption   QuestionOptionValue 
Beach and Recreation  eamil@gmail.com; email@AOL.COM 

어떻게 추가 할 필요가 어디 않습니다 돌아가려면?

Answer 1

에서 다음 쿼리

Select 
    QuestionOption, GROUP_CONCAT(QuestionOptionValue SEPARATOR ' ') as QuestionOptionValue 
FROM 
    Table1 
GROUP BY 
    QuestionOption 

데모를 사용할 수 있습니다

SELECT 'Beach and Recreation' as QuestionOption, Stuff((SELECT N'; '+U.email FROM 
Users AS U JOIN UserProfile ON U.UserID = UserProfile.UserID 
where UserProfile.PropertyValue='Beach and Recreation' FOR XML 
PATH(''),TYPE).value('text()[1]','nvarchar(max)'),1,2,N'') as QuestionOptionValue 
union SELECT 'CC/Web Page' as QuestionOption, Stuff((SELECT N'; '+U.email FROM Users 
AS U JOIN UserProfile ON U.UserID = UserProfile.UserID 
where UserProfile.PropertyValue='CC/Web Page' FOR XML PATH(''),TYPE).value('text()  
[1]','nvarchar(max)'),1,2,N'') as QuestionOptionValue union 
SELECT 'Civic Association Board' as QuestionOption, Stuff((SELECT N'; '+U.email FROM 
Users AS U JOIN UserProfile ON U.UserID = UserProfile.UserID 
where UserProfile.PropertyValue='Civic Association Board' FOR XML 
PATH(''),TYPE).value('text()[1]','nvarchar(max)'),1,2,N'') as QuestionOptionValue union 
SELECT 'Clubhouse Rentals' as QuestionOption, Stuff((SELECT N'; '+U.email FROM Users 
AS U JOIN UserProfile ON U.UserID = UserProfile.UserID 
where UserProfile.PropertyValue='Clubhouse Rentals' FOR XML 
PATH(''),TYPE).value('text()[1]','nvarchar(max)'),1,2,N'') as QuestionOptionValue union 
SELECT 'Fundraising Committee' as QuestionOption, Stuff((SELECT N'; '+U.email FROM 
Users AS U JOIN UserProfile ON U.UserID = UserProfile.UserID 
where UserProfile.PropertyValue='Fundraising Committee' FOR XML 
PATH(''),TYPE).value('text()[1]','nvarchar(max)'),1,2,N'') as QuestionOptionValue 
Union SELECT 'Lake Preservation' as QuestionOption, Stuff((SELECT N'; 
'+U.emailFROM  
Users AS U JOIN UserProfile ON U.UserID = UserProfile.UserID 
where UserProfile.PropertyValue='Lake Preservation' FOR XML 
PATH(''),TYPE).value('text()[1]','nvarchar(max)'),1,2,N'') as QuestionOptionValue 
Union SELECT 'Lifeguard Committee' as QuestionOption, Stuff((SELECT N'; '+U.email 
FROM Users AS U JOIN UserProfile ON U.UserID = UserProfile.UserID 
where UserProfile.PropertyValue='Lifeguard Committee' FOR XML  
PATH(''),TYPE).value('text()[1]','nvarchar(max)'),1,2,N'') as QuestionOptionValue 
Union SELECT 'Night Watch' as QuestionOption, Stuff((SELECT N'; '+U.email FROM Users 
AS U JOIN UserProfile ON U.UserID = UserProfile.UserID 
where UserProfile.PropertyValue='Night Watch' FOR XML PATH(''),TYPE).value('text() 
[1]','nvarchar(max)'),1,2,N'') as QuestionOptionValue Union 
SELECT 'Volunteer Committee' as QuestionOption, Stuff((SELECT N'; '+U.email FROM 
Users AS U JOIN UserProfile ON U.UserID = UserProfile.UserID 
where UserProfile.PropertyValue='Volunteer Committee' FOR XML 
PATH(''),TYPE).value('text()[1]','nvarchar(max)'),1,2,N'') as QuestionOptionValue 

Answer 2

은 MYSQL의 경우 당신은 내가는 여기를 알아내는 최대 eneded http://sqlfiddle.com/#!2/db6b5a/2