R 테이블의 수직 데이터 그룹 R

Question

관계를 찾기 위해 서로에 대해 플롯해야하는 7 개의 세로 열 그룹의 테이블에 데이터가 있습니다. 그룹을 7 개 그룹으로 세로로 그룹화하는 방법과 멋진 그래픽에 유용한 플롯은 무엇입니까? 나는 적당하다고 생각되는 "차"를 보았다. A_0, A_4, A_5, A_6, B_0, B_1, B_2, B_3, B_4, B_5, B_6, C_0, C_1, C_2, C_3, C_4, C_5, C_6, D_0, D_1, D_2, D_3의 A_0, A_1, A_2, A_3, D_4, E_5, E_6, D_4, D_5, D_6, D_0, D_1, D_2, D_3, D_4, D_5, D_6, E_0, E_1, E_2, , 1,0011100.000003000.000004,0.000004,0.00000401001110200,1 , 1,1,0,0.000003000.000002,0.000002,0.000002 2,1,0000421000040.000007,0.000003 , 0,0,0,0,0.000012110000121000040.000003,0.0000020000 , 0.000006 1,00004110000410.0000030000.000012,0.0000031000 , 001110000410.00000200000.000006,0.000002 1,0,0,1,0,0,1 , 1,0010010.000003000.000003000.0000011001001100,1 , 0,0,1,0.000002000.000001000 010, 0.000003000.000001,0.000002,0.0000030100111010.000001000 , 0.000001,0.000 002 1,0.000003000.000001,0.000002,0.0000030100, 1,1,1,010.0000010000.000001,0.000002,0 1,0,0,0,2,0,2, 1,0002020.0000010000.000002,0,0.00000210001011000, 2,0200000.000001,0,0.000001 020001102000110, 0.0000020000.000001,0.0000010100011020001100.000001000, 0.2,00011220001120.0000020000.000001,0.000001,0.000002,1,0, 0011120001120.0000010000.000001,0,0.000001 0,1,1,2,2,0, 1, 2,2,0,3,0,0.000001,0,0.000001,0.000001,0,0.000001 1,1,2,2,0311220,2,1, 0.000001,0.000001,0.000002,0.000002,0,0.000003,0.00000111110111220310.000001,0,0.000001,0.000001, 0,0.000001,0 .000001 011122001112000.000001,0.000001,0.000001,0.000002,0.000002,0,0,1,1 , 1,1,1,0011122000.000001,0.000001,0,0.000001,0.000001,0 0,1,1,0,0,0,12 , 011000600.000001,0.0000010000.00000701100010110 , 00120000000.000006 1,1,00.000001 , 0.0000010000.000007,0.00001711000111100, 0.000006,0.000015 1,00.0000010000.000007,0.000017,0.000001,1,0 , 00111100.000006,0.000015,0 1,0,13,4,11,9 , 1000121570.000001,0,0.000002,0.000002,0.000002,0.000005,0.000008101111110,13 , 4,11,9,10,0,0,0.000006,0.000002,0.000005,0.000004,0.000005 013411910180,1,2,1,5,7,4 , 0, 0, 000, 2000, 2000, 2000, 2000, 1,9,10,18,0,0.000006,0.000002,0.000005,0.000004,0.000005,0.000008 13,4,11,9,10,18,39,1,2,1,5,7,4,9, 0.000002,0.000002,0.000002,0.000005,0.000008,0.000006,0.0000111111111341191018390.000006,0.000002,0.000005,0.000004, 0.000005,0.000008,0.000017 4119101839821574940.000002,0.000002,0.000005,0.000008,0.000006,0.000011,0.000005,1, 1,1,1,1,1,4,11,9,10,18,39,8,0.000002,0.000005,0.000004,0.000005,0.000008,0.000017,0.000004 11,9,10,18,39, 8.16, 1018398160.000005,0.000004,0.000005,0.000008,0.000017,0.000004,0.000007 9,1018398160,5,7,4,9,4,5, 0,0.000005,0.000008,0.000006,0.000011,0.000005,0.00000601111110910183981600.000004,0.000005,0.000008, 0.000017,0.000004,0.000007,0 1,01600210130, 0,2,0.000001,0,0.000001,0.000003000.0000021011001101600200, 0,0.000003000.000001 0160022013002200.000001,0.000003000.000002, 0.00000201100110160022000.000003000.000001,0.000001 0,2,2, 0, 0, 0, 0, 0, 2, 02200171900.000001,0.000001000.000008,0.000009 2,2,008412200, 8,4,1,0.000002,0.000002000.000011,0.000006,0.00000211001112200171930.000001, 0.000001000.00000800000090.000001 2,00841120084120.000002000.000011,0.000006,0.000002,0.000003,1,0, 0,1,1,1,0.5,2,001719350.000001000.000008,0.000009,0.000001,0.000002

Answer 1

데이터를 입력하지 않았거나 어떤 종류의 차트, 나는 버블 플롯을 가정 한 테스트되지 않은 코드를 넣어야한다. -

library(ggplot2) 
library(reshape2 

datamelted <- melt(data, id.vars = 'ABcol') 
ggplot(datamelted, aes(x = ABcol, y = variable, size = value) + geom_point()