저장 프로 시저에서 여러 테이블에 삽입하는 방법

Question

데이터를 열에 삽입하지만 올바른 열에로드되지 않는 다음 코드가 있습니다. 잘못된 것이 무엇입니까?

ALTER PROCEDURE [dbo].[spTESt] 
AS 

DECLARE @Report TABLE (
    c1 int, c2 int, c3 int, c4 int, c5 int 
) 


INSERT INTO @Report (c1) 
SELECT mass as c1 FROM other_sales 
WHERE id='17501' order by mass 

INSERT INTO @Report (c2) 
SELECT mass as c2 FROM other_sales 
WHERE id='17154' order by mass 


INSERT INTO @Report (c3) 
SELECT mass FROM other_sales 
WHERE id='17156' order by mass 


INSERT INTO @Report (c4) 
SELECT mass FROM other_sales 
WHERE id='17500' order by mass 


INSERT INTO @Report (c5) 
SELECT mass FROM other_sales 
WHERE id='17501' order by mass 

조건에 따라 별도의 열로 이동해야합니다. 다르게 구조해야합니까? 다음과 같이

Answer 1

DECLARE 
     @Report TABLE (

c1 int , 
c2 int , 
c3 int , 
c4 int , 
c5 int 

    ) 

DECLARE @_C1 INT 
DECLARE @_C2 INT 
DECLARE @_C3 INT 
DECLARE @_C4 INT 
DECLARE @_C5 INT 

SELECT @_C1 = mass FROM other_sales 
WHERE id='17501' order by mass 

SELECT @_C2 = mass FROM other_sales 
WHERE id='17154' order by mass 

SELECT @_C3 = mass other_sales 
WHERE id='17156' order by mass 

SELECT @_C4 = mass other_sales 
WHERE id='17500' order by mass 

SELECT @_C5 = mass other_sales 
WHERE id='17501' order by mass 

INSERT INTO @Report 
     (c1, c2, c3, c4 , c5) 
VALUES (@_C1, -- c1 - int 
      @_C2, -- c2 - int 
      @_C3, -- c3 - int 
      @_C4, -- c4 - int 
      @_C5 -- c5 - int 
     ) 

Answer 2

모든 select 문이 값을 returnsingle 가정 마지막 열 선언

DECLARE 
     @Report TABLE (

c1 int , 
c2 int , 
c3 int , 
c4 int 

    ) 

Answer 3

후 쉼표를 제거, 당신은 하나의 문을 시도 할 수 :

ALTER PROCEDURE [dbo].[spTESt] 
AS 
--...... 
DECLARE @Report TABLE (c1 int, c2 int, c3 int, c4 int, c5 int) 

INSERT INTO @Report (c1, c2, c3, c4, c5) values (
(SELECT mass FROM other_sales WHERE id='17501'), 
(SELECT mass FROM other_sales WHERE id='17154'), 
(SELECT mass FROM other_sales WHERE id='17156'), 
(SELECT mass FROM other_sales WHERE id='17500'), 
(SELECT mass FROM other_sales WHERE id='17501')) 
--....